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Arturiano [62]
3 years ago
8

Y= -2x 7x-8y=-23 Solve the system using the substitution method

Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

x=-1 and y=2

Step-by-step explanation:

substitute -2x for y in 7x-8y=-23

7x-8y=-23

7x-8-2x=-23

23x=-23

x=-1

substitute -1 for x in y=-2x

y=-2x

y=(-2)(-1)

y=2

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Simplificar expresiones lineales<br>-2+7m-7m+5m​
Helen [10]

Answer:

I am not sure it correct or not but I try to answer

Step-by-step explanation:

0-2+7m-7m+5m=7

8 0
3 years ago
F(a) = 2a<br> gla) = 4a - 3<br> Find f(g(-1))
Annette [7]

Answer:

first deal with g(-1)

y=4a - 3

a=4y -3 and now make y the subject again

a+3/4...now put it into f(a)

2(a +3/4) simplyifying

a+3/2 as yo final ans

3 0
3 years ago
gina has 48 stickers 3/8 of the stickers have pictures of flowers. 1/8 of the stickers have pictures with plants. the rest of th
irinina [24]

Answer:

24 stickers of people

Step-by-step explanation:

you have 48 stickers in total, therefore make the denominator equal 48 by muliplying each fraction by 6/6

3/8 x 6/6 = 18/48

1/8 x 6/6 = 6/48

add those together to get the total stickers without people

18/48 + 6/48 = 24/48

this means half don't have people

then you can subract that number from the total and you will find the stickers with pictures of people

48/48 - 24/48

24/48

8 0
4 years ago
Read 2 more answers
Does the point (5, 8) satisfy the inequality 2x + y &gt; 18?​
Anarel [89]

Answer:

The answer is...... NO

Step-by-step explanation:

Step 1: Plug in your values in the x and y cordinates.

2(5) + 8 > 18

Step 2: Solve

Then you multiply 2 and 5 and get 10.

SO then your equation should look like this:

10 + 8 > 18

The answer to the question is no because in order for this to work it would need to be the greater than or equal to sign, which looks like this ≥.

Hope this helps and have a great day! :)

7 0
3 years ago
How to describe partial products yo 4th grader
erastova [34]

To describe partial products in a "laymans" term, you'd have to set up an problem with the 4th grader.

Set it up in a big format and even make a game out of it with tiles on the floor.

Explain to the 4th grader that the number on the bottom will be multiplied by each number separately and then eventually added. For more than one digit multiplication problems, they add a "0" for each number they are on. Example: One zero after the first number is multiplied. Two zero's after the second number is multiplied, etc...

Then, you just add like normal.


I have actually used the tile method to help my 4th grader learn how to do partial products.

I suggest making BIG 8x10 numbers. Then, tape them (gently) on the floor. Have the 4th grader stand on the first number they'd be multiplying. Example:

12 x 6

The student would stand on the number 6. You then ask them to jump (or hop-just be careful of slippery surfaces) on the number they have to multiply with next; which would be the 2. You'd ask them, what is "6 x 2?". They should reply with 12.

Next, have another set of smaller numbers where they can come back and place the numbers. 2 would go on the bottom and they hold the 1 so they can remember they need to add it to the next multiplication number.

So, now you'd have them stand on the number 6 again. Ask where they have to multiply again. They should move to the 1. Ask what is "6x1". Then answer should be 6. Then remind them they are holding a number and what they should do with it. The answer should be "add it to the answer of the multiplication". So, it should be 6+1=7. Then, they'd place the number 7 at the bottom of the problem.

Once they figure it out with single digits, move onto double digits at the bottom and work up from there.  

This way, they are having to use BIG movements and will eventually gain muscle memory on which directions and how to multiple correctly.


GOOD LUCK!

3 0
3 years ago
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