All categories

3 years ago

Solve the following equation 4a - 4 = 8 +a

Mathematics

2 answers:

lubasha [3.4K]3 years ago

8 0

The answer to the equation is a=4

seropon [69]3 years ago

8 0

Answer:

a= 4

Step-by-step explanation:

here's your solution

=> 4a - 4 = 8 + a

=> 4a - a = 8 + 4

=> 3a = 12

=> a= 12/3

=> a = 4

hope it helps

You might be interested in

What ratio is 25 to 16

Studentka2010 [4]

25:16 just as you see it, the "to" represents the semicolon and just put it together and you can't simplify it so the answer is 25:16

7 0

3 years ago

Read 2 more answers

Solve 2x^2+3x-2 when x=5

viktelen [127]

Answer:

Step-by-step explanation:

2(5)²+3(5)-2

50+15-2

using bodmas

65-2

8 0

3 years ago

Read 2 more answers

What is the factored form of the expression 5p^3-10p^2+3p-6

Ugo [173]

Answer: (5p^2+3)(p-2)

Step-by-step explanation:

In this problem, we need to write the factor form of expression .

5p^3-10p^2+3p-6

It can be done as follows :

5p^3-10p^2+3p-6=(5p^3+3p)+(-10p^2-6)

Taking common form the terms as follows :

=p(5p^2+3)-2(5p^2+3)

It can be also written as :

=(5p^2 +3)(p-2)

Hence, the factored form of is

5 0

3 years ago

Read 2 more answers

write the equation of the line that passes through the points 7, -4 and -1, 3 first and point-slope form and then in slope inter

anyanavicka [17]

The slope of line is $\frac{-7}{8}$

The point slope form is found when point (7, -4) is used is $y + 4 = \frac{-7}{8}(x - 7)$

The slope intercept form is $y = \frac{-7}{8}x + \frac{17}{8}$

<em><u>Solution:</u></em>

We have to find the equation of the line that passes through the points 7, -4 and -1, 3

<h3><u>Point slope form:</u></h3>

The point slope form is given as:

$y - y_1 = m(x - x_1)$

Where "m" is the slope of line

Given two points are (7, -4) and (-1, 3)

<h3><u>Let us find the slope of line</u></h3>

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting $(x_1 , y_1 ) = (7, -4) \text{ and } (x_2, y_2) = (-1, 3)$

$m=\frac{3-(-4)}{-1-7}=\frac{7}{-8}$

$m=\frac{-7}{8}$

Thus slope of line is found

Substitute value of m and point (7, -4) in eqn 1

$y - (-4) = \frac{-7}{8}(x - 7)\\\\y + 4 = \frac{-7}{8}(x - 7)$

Thus the point slope form is found when point (7, -4) is used

<h3><u>Slope intercept form:</u></h3>

The slope intercept form is given as:

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Substitute m = -7/8 and (x, y) = (7, -4) in eqn 1

$-4 = \frac{-7}{8}(7) + c\\\\-32 = -49 + 8c\\\\8c = 17\\\\c = \frac{17}{8}$

Substitute m = -7/8 and $c = \frac{17}{8}$ in eqn 1

$y = \frac{-7}{8}x + \frac{17}{8}$

Thus the required equation of line is found

8 0

3 years ago

Read 2 more answers

Topic: Finite Geometric Sums <br> what is the value of ..

kobusy [5.1K]

$\bf \sum\limits_{i=a_1}^{a_n}\ a1\cdot (r)^{n-1}\iff S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\qquad 
\begin{cases}
a_1=\textit{first term}\\
r=\textit{common ratio}\\
n=n^{th}\ term
\end{cases}\\\\
-----------------------------\\\\

\begin{array}{llll}
\sum\limits_{i=1}^{3}\ &4\cdot \left( \frac{1}{2} \right)^{i-1}\\
&\uparrow \quad \uparrow \\
&a_1\quad r
\end{array}\iff S_3=4\left( \cfrac{1-\left( \frac{1}{2} \right)^3}{1-\left( \frac{1}{2} \right)} \right)$

7 0

3 years ago