Answer:
The second expression is not equivalent to the initial expression.
Step-by-step explanation:
Given:
.
Clubbing the co-efficient of g and constant terms. we get:
![$ \frac{1}{10}g + (-1)g + 1\frac{3}{10}g + -\frac{1}{10} + - \frac{1}{10} $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B1%7D%7B10%7Dg%20%2B%20%28-1%29g%20%2B%201%5Cfrac%7B3%7D%7B10%7Dg%20%2B%20-%5Cfrac%7B1%7D%7B10%7D%20%2B%20-%20%5Cfrac%7B1%7D%7B10%7D%20%24)
This is the first step and is equivalent to the initial expression.
Now, Simplifying the above expression we have:
![$ \frac{1}{5}g - g + \frac{13}{10}g + (- \frac{2}{10} )$](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B1%7D%7B5%7Dg%20-%20g%20%2B%20%5Cfrac%7B13%7D%7B10%7Dg%20%2B%20%28-%20%5Cfrac%7B2%7D%7B10%7D%20%29%24)
⇒ ![$ ( \frac{1}{5} - 1 + \frac{13}{10}) g $](https://tex.z-dn.net/?f=%24%20%28%20%5Cfrac%7B1%7D%7B5%7D%20-%201%20%2B%20%5Cfrac%7B13%7D%7B10%7D%29%20g%20%24)
⇒ ![$ g (\frac{2 -10 + 13}{10}) - \frac{2}{10} $](https://tex.z-dn.net/?f=%24%20g%20%28%5Cfrac%7B2%20-10%20%2B%2013%7D%7B10%7D%29%20-%20%5Cfrac%7B2%7D%7B10%7D%20%24)
⇒![$ \frac{5}{10}g - \frac{2}{10} $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B5%7D%7B10%7Dg%20-%20%5Cfrac%7B2%7D%7B10%7D%20%24)
⇒ ![$ \frac{1}{2}g - \frac{1}{5} $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B1%7D%7B2%7Dg%20-%20%5Cfrac%7B1%7D%7B5%7D%20%24)
This is not the second step done by him. Not equivalent to the initial step.
Answer:
19
Step-by-step explanation:
Set denominator to zero and solve for x.
x^2 - x - 12 = 0
Factor.
(x - 4)(x + 3) = 0
Solve each factor for x.
x - 4 = 0
x = 4
x + 3 = 0
x = -3
Answer:
The domain is ALL REAL NUMBERS except for x = 4 and x = -3.
Answer:0.15151515/1
Step-by-step explanation:
Simple...
you have: (3,6) and the slope is 8...
Using y=mx+b and using the coordinates provided....
6=8(3)+b
6=24+b
6=24+b
-24 -24
-18=b
y=8x-18
Thus, your answer.