Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
Answer:
Step-by-step explanation:
I hope I did this right:
So first thing to do is set up the equation.
Next thing to to is subtract 1/3 from both sides to get:
Next up, you will multiply each of the fractions by the opposing value
(multiply 1/8 by 3 and 1/3 by 8)
Alright almost done, by multiplying 24 by 5 you get 120, that will go in the numerator to make the math a lot easier.
K = 
Finally, you subtract 123 over 24 by 8 over 24.
K = 
Then just simplfy the 115/24 to get
With a 12% discount, 18.48 is the price per ticket (2.52 per ticket saved). In order to determine the amount of tickets, we divide the saved amount by the amount saved per ticket.
819/2.52 is 325.
There were 325 tickets purchsed.
3, 1, -1, -3, -5
-2 -2 -2 -2
a(n) = a₁ + d(n - 1)
a(n) = 3 - 2(n - 1)
a(n) = 3 - 2(n) + 2(1)
a(n) = 3 - 2n + 2
a(n) = -2n + 3 + 2
a(n) = -2n + 5
a₁₄ = -2(14) + 5
a₁₄ = -28 + 5
a₁₄ = -23
The answer is C.
Answer:
3.5x + 2.50y = 1237.50
425 = x + y
Step-by-step explanation:
number of adult tickets: x
number of student tickets: y
3.5x + 2.50y = 1237.50
( value of adult ticket [3.50]* number of adult tickets [x]) + (value of student ticket [2.50] * number of student tickets [y]) = total value (1237.50)
425 = x + y
(number of adult tickets [x]) + (number of student tickets [y]) = total (425)
