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3 years ago

Help pleasee! Thank uu

Mathematics

2 answers:

ololo11 [35]3 years ago

8 0

Answer:

The answer is the 2nd option

Step-by-step explanation:

djyliett [7]3 years ago

5 0

..................the y intercept

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At school assembly four out of the first 10 students are wearing spirt wear. Based on this information, if 500 students were at

8090 [49]

Answer=125
Step by step=
Well if 10 x 50 is 500 (just to show how you get doesn't affect problem) you would simply divide by 4 thus, you get 125

6 0

3 years ago

Can someone please help with my math real quick?

Jobisdone [24]

Answer:

5.0003 x 10^-5

I believe this is the answer!

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive. Hope this helps!

4 0

3 years ago

write an Equation for the angle relationship shown in the figure and solve for x. Find the measures of RQS and TQU?

Dvinal [7]

Answer:

∠RQS = 21°

∠TQU = 28°

Step-by-step explanation:

90° + 221° + 3x + 4x = 360°

combine like terms:

7x + 311° = 360°

subtract 311° from each side of the equation:

7x = 49°

divide both sides by 7:

x = 7°

∠RQS = 3x = 3(7°) = 21°

∠TQU = 4x = 4(7°) = 28°

4 0

3 years ago

Rufus appears before Bill and Ted and offers them a bogus proposition: they must paint a house together with their magical guita

jolli1 [7]

Answer:

6.79

Step-by-step explanation:

-Let X denote the total amount of the job.

-The job has to be done in 5 hrs, therefore the portion done every hour is:

$Rate=\frac{Total}{Time}\\\\=\frac{X}{5}\\\\=\frac{1}{5}X=0.2X$

Therefore, the rate of Bill and Ted working jointly must equal the rate calculated above:

$R_{Bill}=\frac{X}{19}\\\\=\frac{1}{19}X\\\\R_{Bill}+R_{Ted}=R_{required}\\\\\frac{1}{19}X+R_{Ted}=\frac{1}{5}X\\\\R_{Ted}=\frac{1}{5}X-\frac{1}{19}X\\\\=\frac{14}{95}X\\\\\therefore \frac{14}{95}X=1\ hr\\\\X=1\div \frac{14}{95}\\\\=6.7857\approx 6.79$ $hrs$

Hence, Bill working alone should complete the house in 6.79 hrs

6 0

3 years ago

Consider the function f(x, y) = x2 + xy + y2 defined on the unit disc, namely, d = {(x, y)| x2 + y2 ≤ 1}. use the method of lagr

Pani-rosa [81]

First we note that the partial derivatives vanish simultaneously at one point:

$\begin{cases}f_x=2x+y=0\\f_y=x+2y=0\end{cases}\implies(x,y)=(0,0)$

so there is one critical point within the region $D$ .

The Lagrangian is

$L(x,y,\lambda)=x^2+xy+y^2+\lambda(x^2+y^2-1)$

and has partial derivatives

$L_x=2x+y+2\lambda x$
$L_y=x+2y+2\lambda y$
$L_\lambda=x^2+y^2-1$

Set each partial derivative to 0 to find the possible critical points within the disk $D$ . Then we notice that

$yL_x=2xy+y^2+2\lambda xy=0$
$xL_y=x^2+2xy+2\lambda xy=0$
$L_\lambda=0\implies x^2+y^2=1$

$\implies xL_y-yL_x=x^2-y^2=0$

Since $x^2+y^2=1$ , we have

$x^2-y^2=x^2+y^2-2y^2=0\implies1=2y^2\implies y^2=\dfrac12\implies y=\pm\dfrac1{\sqrt2}$

And since $x^2-y^2=0$ , or $x^2=y^2$ , we also have

$x=\pm\dfrac1{\sqrt2}$

So we have four possible additional critical points to consider:

$f(0,0)=0$
$f\left(-\dfrac1{\sqrt2},-\dfrac1{\sqrt2}\right)=\dfrac32$
$f\left(-\dfrac1{\sqrt2},\dfrac1{\sqrt2}\right)=\dfrac12$
$f\left(\dfrac1{\sqrt2},-\dfrac1{\sqrt2}\right)=\dfrac12$
$f\left(\dfrac1{\sqrt2},\dfrac1{\sqrt2}\right)=\dfrac32$

It should be clear enough which of these correspond to the absolute extrema of $f$ over $D$ .

8 0

3 years ago