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nataly862011 [7]
3 years ago
9

234 is 45% of what amount

Mathematics
1 answer:
GaryK [48]3 years ago
3 0

Answer:

520?

Step-by-step explanation:

I think

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How many times dose 25 go into 150
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This is the easiest way to memorize how to multiply using the number 25.
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P=−4b 2 +6b−9 <br> Q=7b 2 −2b−5<br> ​P−Q=<br> Your answer should be a polynomial in standard form.
shepuryov [24]

Answer:

−11b^2+8b−4

Step-by-step explanation:

−4b2+6b−9−7b2+2b+5

Simplify by adding terms.

11b2+8b−4

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3 years ago
Compare and contrast the following two equations. Determine if they are linear equations and explain why or why not.
igor_vitrenko [27]

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xy = -1 and y = -1/x are the same.

They are not linear equations because they are not written in the form

Ax + By = C.

7 0
2 years ago
Question number 4 please help
Korvikt [17]
\frac{x^2+x-30}{x^2-3x+2}\\\\x^2-3x+2=0\\\\x^2-x-2x+2=0\\\\x(x-1)-2(x-1)=0\\\\(x-1)(x-2)=0\iff x-1=0\ \vee\ x-2=0\\\\x=1\ \vee\ x=2\\\\Answer:For\ x=1\ or\ x=2.
8 0
3 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
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