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jenyasd209 [6]
3 years ago
9

In ΔWXY, w = 130 inches, y = 130 inches and ∠Y=125°. Find all possible values of ∠W, to the nearest degree.

Mathematics
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

No Possible Triangles

Step-by-step explanation:

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Helppppppppppppppppppppppppppppppppppppppppppppppp
Rama09 [41]
I have 3 answers for u
1st. STOP SLACKING AND DO YOU WORK
2nd. Look at the video
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8 0
3 years ago
Read 2 more answers
Assign two variables for each problem, and write the equations. Do not solve.
Xelga [282]
Call the number of trumpet players "T" and the number of horn players "H".

We can use the given information to set up equations:

1."<span>the number of trumpet players is 4 times the number of French horn players"
T=4H

2. "</span><span>There are 35 trumpet and French horn players in the band."
T+H=35

If you were asked to solve you could now do it by substitution:
4H+H=35
5H=35
H=7
T=4H
T=4(7)
T=28</span>
7 0
3 years ago
Either use technology to find the P-value or use
Akimi4 [234]

Answer:

The first step is calculate the degrees of freedom, on this case:  

df=n-1=21-1=20  

Since is a one side left tailed test the p value would be:  

p_v =P(t_{(20)}  

And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"

Step-by-step explanation:

Data given and notation  

\bar X represent the mean

s represent the sample standard deviation

n=21 sample size  

\mu_o =140 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t=-0.024 would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean for the widths of tornadoes is lower than 140 yd, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

The statistic is given by: t = -0.024

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=21-1=20  

Since is a one side left tailed test the p value would be:  

p_v =P(t_{(20)}  

And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"

Based on the p value obtained we can conclude that we FAIL to reject the null hypothesis at any significance level selected \alpah=0.01,0.05,0.1

7 0
3 years ago
WILL GIVE BRAINLEIST
DanielleElmas [232]

Answer: Last option ("Each term in the second sequence is one-third the corresponding term in the first sequence.")

Explanation:

First, you need to understand what the rules are saying. I find it useful to write them as equations, but everyone's different. Especially for this situation, making a table should be really helpful.

Rule 1: add 6 starting from 0

Add 6 each time. The "add" part should tell you that it's the slope. The equation has a slope of 6. "Starting from 0" tells you that the y-intercept is 0. Using slope-intercept form (y=mx+b, where m is the slope and b is the y-intercept), you can write the equation as y=6x+0, or y=6x.

Rule 2: add 2 starting from 0

2 is the slope and 0 is the y-intercept. y=2x

You didn't <em>have</em> to do this part, but it makes the rules easier to understand. Now you can easily make a table to find the relationship between the rules. First, pick some values of x to use:

Rule 1:

x  |    1   |   2  |   3

y  |         |       |

Rule 2:

x  |    1   |   2  |   3

y  |         |       |

(They're supposed to be tables with only the x-values filled in.)

Using the equations, or only the rules, you can fill in the tables.

You can use more than 3 values of x, but I think this is enough.

x=1:

Rule 1: y=6x

             =6(1)

            =6

Rule 2: y=2x

              =2(1)

              =2

Do the same thing for y when x=2 and x=3. Then you can fill in the tables to get:

Rule 1:

x  |    1   |   2  |   3

y  |    6  |  12  |   18

Rule 2:

x  |    1   |   2  |   3

y  |    2  |   4  |   6

Since you've organized the values now, it'll be much simpler to find the relationship between the rules. Observe the y-values.

When x=1, rule 1 results in 6, and rule 2 results in 2. Now look at each option in the answers.

"Each term in the second sequence is three times the corresponding term in the first sequence."

In the first sequence, you have 6 when x=1. If the corresponding term in the second sequence has to be 3 times that, it would have to be 18. This one doesn't work.

"Each term in the first sequence is one-third the corresponding term in the second sequence."

This is saying the same thing as the previous option. It doesn't work.

"Each term in the first sequence is six times the corresponding term in the second sequence."

When x=1, y in the second sequence is 2. 6 times that is 12, but the value in the first sequence is only 6. This option is incorrect as well.

"Each term in the second sequence is one-third the corresponding term in the first sequence."

2/6=1/3, so this one does work. You could have arrivived at this conclusion earlier by just dividing, but I wanted to explain why the rest don't work.

Hope I could help!

4 0
3 years ago
12y+d=−19y+t does anyone know the answer
IRINA_888 [86]
Hello Aboswell05,  Let's solve for d.<span><span><span> 12y</span>+d</span>=<span><span>−<span>19y</span></span>+t</span></span> Step 1: Add -12y to both sides.<span><span /></span><span><span><span> d+<span>12y</span></span>+<span>−<span>12y</span></span></span>=<span><span>t−<span>19y</span></span>+<span>−<span>12y</span></span></span></span><span /><span> d=<span>t−<span>31y</span></span></span>Answer:<span> d=<span>t−<span>31y. if this is not the answer correct me and ill redo the question.
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6 0
3 years ago
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