2 years ago

What is the equation of Ceres’ elliptical orbit in standard form?

Mathematics

1 answer:

erik [133]2 years ago

3 0

Answer:

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Step-by-step explanation:

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Write the equation in standard form.<br><br> 3x−9=7y

Ket [755]

In standard form the answer will be if you go by (Ax+by=c )then I must say it's 3x-7y=9

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2 years ago

No one will answer this probably wasting my points XD) Spunky the terrier is chasing a chicken. Spunky runs at a rate of r feet

Vesna [10]

It sucks that points have to be used in order to post questions.

Openstudy - the company that merged into Brainly - was much better.

Anyway, I think that the answer to this question is A. I'm not sure, though.

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2 years ago

Members of a lacrosse team raised $1793.50 to go to a tournament. They rented a bus for $757.50 and budgeted $64.75 per player f

Alona [7]

Answer:

757.5+64.75= 822.25

Step-by-step explanation:

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2 years ago

PLEASE ANSWER ILL GIVE BRAINLIEST

balu736 [363]

Answer:

i believe the answer is 2.5 ft cubed.

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3 years ago

PLEASE HELP ME FOR BRAINLIEST!!!!

vekshin1

Answer:

A=52.8 miles (approximately)

Step-by-step explanation:

We can assume that this triangle is not a right angle, therefore we cannot use Pythagorean theorem. Let's use the Law of Sines:

$\frac{sin(A)}{a}=\frac{sin(B)}{b}=\frac{sin(C)}{c}$

Where A is unknown, a=28 miles, b=32 miles, B=87°

Therefore by law of sines we have:

$\frac{sin(A)}{28} =\frac{sin(87)}{32} \\$

By multiplying 28 to Isolate sin(A) we have:

$sin(A)=\frac{28*sin(87)}{32}$

To cancel out sine on the right, we must multiply both by the inverse sine and so:

$A=sin^{-1}(\frac{28*sin(87)}{32})=52.7658\\ \\A=52.8mi$

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2 years ago