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Umnica [9.8K]
2 years ago
11

What is the equation of Ceres’ elliptical orbit in standard form?

Mathematics
1 answer:
erik [133]2 years ago
3 0

Answer:

I'm on the same problem! Search it up

Step-by-step explanation:

You might be interested in
What is 4/5 of 45 equle
Goryan [66]
\frac{4}{5} \ of \ 45= \frac{4}{5} \times 45=4 \times \frac{45}{5}=4 \times 9=36

4/5 of 45 equals 36.
5 0
3 years ago
Read 2 more answers
PLEASE HELO ASAP WILL MARK BRAINLIEST
ss7ja [257]
A.) 1/2

B.) 3

For the first one, just plug the value of x (4) everywhere you see x in the formula.

For the second one, place 1 wherever you see f(x)

Hope this helps
6 0
2 years ago
HELP!!!! Find the area. Simplify your answer.<br> 552-9s<br> 3t2+t
Tems11 [23]

Answer:

A = (5s^2t - 9st) (3t + 1)

Step-by-step explanation:

(5s^2 - 9s) (3t^2 + t)

= 15s2t^2 + 5s^2t - 27st^2 - 9st

= 5s2t (3t + 1) - 9st (3t + 1)

= ( 5s^2t - 9st) (3t+1)

6 0
2 years ago
WILL MARK BRAINLEST HELP ASAP!!!!!
astra-53 [7]

Answer:

Area of the rectangle is 10x²+7-6

Step-by-step explanation:

Area of rectangle is the product of its length and width

As length of given rectangle is 5x+6 and its width is 2x-3 the are is

(5x+3)(2x-3)

=5x·2x-5x+6·2x-6

=10x²-5x+12x-6

=10x²+7x-6

5 0
3 years ago
Read 2 more answers
6. Sketch the region enclosed by the graphs of x =0, 6y-5x=0 and x+3y=21. Find the area
kow [346]
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h

1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6

Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50

3 0
3 years ago
Read 2 more answers
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