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Ivan
3 years ago
11

Please help me I need these answers

Mathematics
1 answer:
vlada-n [284]3 years ago
5 0
I think the second to last one.
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What is the value of x?<br><br> Enter your answer in the box.
12345 [234]
2x - 4 = 60
2x = 64
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hope it helps
5 0
3 years ago
An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
3 years ago
PLEASE help me and PLEASE show the work PLEASE.
Dafna1 [17]

20(4×-2)

________

(4 - (-2))²

simplified;

20(-8)

_____

(6)²

simplified;

-160

______

36

simplified;

-4 16/36

simplified;

-4 4/9


3 0
3 years ago
Tim's phone service charges $26.97 plus an additional $0.25 for each text message sent per month. If Tim's phone bill was $33.22
Stels [109]
B. $0.25x+26.97=$33.22
5 0
3 years ago
Find the total travel time depart 5:30 pm mountain standard time arrive 9:30 pm central time
daser333 [38]

Answer:

5 hours

Step-by-step explanation:

I hope this helps

5 0
3 years ago
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