2 years ago

I need help answering

1 answer:

jekas [21]2 years ago

6 0

Put the values of the variables in place of the variables in the expression, then do the arithmetic.

$8p+3q-18\\\\=8\left(\dfrac{1}{2}\right)+3(7)-18=\dfrac{8}{2}+21-18\\\\=4+21-18\\\\=25-18\\\\=\bf{7}$

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Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: $n(E\cup N=50)$

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For any two event A and B, we have

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

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Hence, 3 students have piercings both on their ears and their noses.

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