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3 years ago

What is the quotient of 13,632 divide by 48

Mathematics

2 answers:

Drupady [299]3 years ago

8 0

Answer:

284

Step-by-step explanation:

13,632/48

Lady_Fox [76]3 years ago

7 0

Answer:

the quotient is 284

Step-by-step explanation:

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What’s is the answer to Simplify 3^5 • 3^4

Mariana [72]

3^9

Step-by-step explanation:

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3 years ago

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1. A linear pair is two adjacent angles that are supplementary and form a straight line.

Stels [109]

The correct awnser is true

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3 years ago

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4:n=6:9 how do you get it?

MAVERICK [17]

Answer:

3.1

Step-by-step explanation:

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3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

12x+7<-11 or 5x-8>40

puteri [66]

Answer:

$\large\boxed{x9\dfrac{3}{5}\to x\in\left(-\infty,\ -1\dfrac{1}{2}\right)\ \cup\ \left(9\dfrac{3}{5},\ \infty\right)}$

Step-by-step explanation:

$12x+7$

$5x-8>40\qquad\text{add 8 to both sides}\\\\5x-8+8>40+8\\\\5x>48\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}>\dfrac{48}{5}\\\\x>\dfrac{48}{5}\\\\x>9\dfrac{3}{5}\\===========================$

$x9\dfrac{3}{5}$

7 0

3 years ago