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3 years ago

I will give brainiest answer

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

8 0

Answer:

≈ 64.43 cm²

Step-by-step explanation:

Subtract the area of the circle from the area of the rectangle.

area of rectangle = 7 × 11 = 77 cm²

area of circle = πr² = π × 2² = 4π cm²

Thus

area of shaded region = 77 - 4π ≈ 64.43 cm² ( to nearest hundredth )

Sindrei [870]3 years ago

8 0

Answer:

The answer might be 64.43 CM. I hope this helps. Please tell me if you get it right or wrong.

Step-by-step explanation:

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Let f (x)=1/x and g (x)=x^2+5x. A. Find (f×g)(x). B. Find the domain and range of (f×g)(x).

Ira Lisetskai [31]

we are given

$f(x)=\frac{1}{x}$

$g(x)=x^2+5x$

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

$(fXg)(x)=\frac{1}{x} (x^2+5x)$

we can simplify it

$(fXg)(x)=\frac{1}{x} (x(x+5))$

$(fXg)(x)=x+5$

(B)

Domain:

Firstly, we will find domain of f(x) , g(x) and (fxg)(x)

and then we can find common domain

Domain of f(x):

$f(x)=\frac{1}{x}$

we know that f(x) is undefined at x=0

so, domain will be

$(-\infty,0)$ ∪ $(0,\infty)$

Domain of g(x):

$g(x)=x^2+5x$

Since, it is polynomial

so, it is defined for all real values of x

now, we can find common domain

so, domain will be

$(-\infty,0)$ ∪ $(0,\infty)$ ..............Answer

Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

Range of f(x):

$f(x)=\frac{1}{x}$

we know that range is all possible values of y for which x is defined

since, horizontal asymptote will be at y=0

so, range is

$(-\infty,0)$ ∪ $(0,\infty)$

Range of g(x):

$g(x)=x^2+5x$

Since, it is quadratic equation

so, its range will be

$[-6.25,\infty)$

now, we can find common range

so, range will be

$(-6.25,0)$ ∪ $(0,\infty)$ .............Answer

6 0

3 years ago

For which of the following equations are x = 5 and x = –5 both solutions?

Minchanka [31]

Short Answer B
Argument
A
A will give you x = +/- 5i
x^2 + 25 = 0
x^2 = - 25 Take the square root.
sqrt(x^2) = +/- sqrt(-25)
x = +/- (5)i which is a complex number.

B
Is the answer
x^2 = 25
sqrt(x)^2 = sqrt(25)
x = +/- 5

C
Can't be factored just by looking at it. You can show that C is not true just by putting 5 into the equation
f(x) = x^2 + 10x - 25
f(5) = 25 + 10*5 - 25
f(5) = 50
C is not true.

D
D can be eliminated as C was
f(x) = x^2 - 5x - 25
f(5) = -25 ( l'll let you show this is not true). 5 is not a solution because it does not make f(x) = 0

6 0

4 years ago

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5x + 2y = 10<br> What is the substitution?

aleksandrvk [35]

Hi there!

The substitutions are 10 and 0.