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slavikrds [6]
3 years ago
14

Please help and choose letter choice

Mathematics
2 answers:
Orlov [11]3 years ago
4 0
The correct answer is a

marusya05 [52]3 years ago
3 0
A would be correct because 2 7/16 is correct
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Two planes are flying towards each other. In 45 minutes, the two planes will be
ELEN [110]

The distance between the two planes will be 800 miles.

It should be noted that the total speed of the two planes will be the sum of their individual speeds. Also, the planes have 1 hour to meet each other.

From the information given, the distance between the planes is 200 miles after they flew for 45 minutes. Therefore, the remaining distance will be:

= 1 hour - 45 minutes = 15 minutes.

The distance between the planes will then be:

= 200/15 × 60

= 200 × 4

= 800 miles

Therefore, the distance between the two planes will be 800 miles.

Read related link on:

brainly.com/question/4490374

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2 years ago
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Find the difference.<br><br> 6rs – (-2rs)
lilavasa [31]
There is no difference, 6rs-(-2rs) if you get rid of the parenthesis you are left with 6rs- -2rs and two negatives make a positive therefore the answer will become 8rs... I hope this helps :)
8 0
3 years ago
Which expression does the model represent?
Fed [463]

Answer:

a

Step-by-step explanation:

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The distance to the nearest exit door is less than 150 feet.
Alja [10]

Answer:

d<150

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6 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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