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2 years ago

7 divided by 6 with whole number Pls help?

Mathematics

2 answers:

adell [148]2 years ago

8 0

Answer:

1.16.. this number cannot be expressed as a whole number, but it can be expressed as a mixed number...

Step-by-step explanation:

Hav a gud day :P

pishuonlain [190]2 years ago

6 0

Answer:

7/6 or 1.166666666667

Step-by-step explanation:

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A storekeeper has two kinds of flour, one selling for 65 cents per pound, and the other selling for 95 cents per pound. How many

Murrr4er [49]

Answer:

The amount of 65 cents per pound flour to use is 40 pounds and the amount of 95 cents per pound flour to use is 60 pounds

Step-by-step explanation:

Let

x ----> amount of 65 cents per pound flour to use

y----> amount of 95 cents per pound flour to use

we know that

$x+y=100$ ----> $y=100-x$ ----> equation A

$0.65x+0.95y=0.83(100)$ ----> equation B

substitute equation A in equation B

$0.65x+0.95(100-x)=0.83(100)$

Solve for x

$0.65x+95-0.95x=83$

$0.95-0.65x=95-83$

$0.30x=12$

$x=40\ lb$

Find the value of y

$y=100-40=60\ lb$

therefore

The amount of 65 cents per pound flour to use is 40 pounds and the amount of 95 cents per pound flour to use is 60 pounds

4 0

3 years ago

Read 2 more answers

11x7/8 pls helpp i am so close from my test being over ty

Feliz [49]

Answer:

Exact Form:

77 /8

Decimal Form:

9.625

Mixed Number Form:

9 5 /8

Step-by-step explanation:

I AM SO SORRY IF THIS IS WRONG

3 0

3 years ago

Read 2 more answers

Rationalize the denominator and simplify. √6/√5-√3

Ann [662]

I hope this is useful

3 0

3 years ago

Please help me solve 1/3x>-4

Naya [18.7K]

Answer:

Step-by-step explanation:

1/3x > -4

cross multiply

1>-4 × 3x

1>-12x

solve for x

x = -1/12

8 0

3 years ago

Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist

yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

and the condition y(1) = 6

We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

6t/(t - 5) is continuous on (-infinity, 5) and (5, +infinity)

We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

But the initial condition is y = 6, when t = 1.

The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0

3 years ago