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3 years ago

9

what is the prescribed dosage of a cretain medicine for a child 6 years old, if the adult dosage facts?what are the steps to sol

ve the provided?

2 answers:

Luda [366]3 years ago

7 0

FOR AN ADUT U USE 4X MORE THAN FOR A CHILD

Julli [10]3 years ago

5 0

C=6/(6+12)∙180
C=6/18∙180
C=1/3∙180/3

Answer: 60

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This ten frame show 5+8 draw to make ten then write the new fact

Butoxors [25]

Draw one ten, (If you have to draw ones, draw 3 of those) and the new fact is 10 + 3. (That equals 13, if you need that.)

7 0

3 years ago

I NEED HELP AND IM ON A TIMED TEST

stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0

3 years ago

Reposting this because no body gave me the equation. An equation would be appreciated :)

o-na [289]

bring the like terms together,

$\frac{6q}{5} + \frac{4q}{5} \leqslant 28 + 3 + 3 - 3$

$\frac{10q}{5} \leqslant 31$

$2q \leqslant 31$

$q \leqslant \frac{31}{2}$

3 0

3 years ago

Read 2 more answers

Find the value of csc theta, if cos =-3/5; 90 degrees < theta < 180 degrees

Sloan [31]

Answer: $\frac{5}{4}$

Step-by-step explanation:

Given

$\cos \theta =\frac{-3}{5}$

and $\theta$ lies between

$90^{\circ}$

and for this $\theta$ , $\sin$ and $\text{cosec}$ is Positive as they lie in 2 nd Quadrant

$\sin ^2\theta +\cos ^2\theta =1$

$\sin ^2\theta =1-(\frac{-3}{5})^2$

$\sin ^2\theta =1-\frac{9}{25}$

$\sin ^2\theta =\frac{16}{25}$

$\sin \theta =\frac{4}{5}$

$\therefore \text{cosec}\ \theta =\frac{5}{4}$

6 0

3 years ago

A survey is being conducted in a county where 62% of the voters are Democrats and 38% are Republican. (a) What is the probabilit

Inessa05 [86]

Answer:

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either the voter is a Democrat, or he is not. The probability of the voter being a Democrat is independent of other voters. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

62% of the voters are Democrats

This means that $p = 0.62$

(a) What is the probability that two independently surveyed voters would both be Democrats?

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.62)^{2}.(0.38)^{0} = 0.3844$

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

3 0

3 years ago