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omeli [17]
3 years ago
10

11. Two students describe how to solve the equation, 23+n=29 . Student A says to add 23 to both sides, while Student B says to s

ubtract 23 from both sides. [3 points]
Part A. Which student has the correct description and why?
Part B. Solve the equation 23 + n =29 using inverse operations.
Mathematics
2 answers:
Goryan [66]3 years ago
8 0

Answer:

You have Ms. Keten too? Tbh I dont like her as a math teacher.

spayn [35]3 years ago
5 0

Answer:

student b

Step-by-step explanation:

the 23 is a positive # so you would not add but subt.

23+n=29

-23     -23

n=6

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Can somebody explain how trigonometric form polar equations are divided/multiplied?
koban [17]

Answer:

Attachment 1 : Option C

Attachment 2 : Option A

Step-by-step explanation:

( 1 ) Expressing the product of z1 and z2 would be as follows,

14\left[\cos \left(\frac{\pi \:}{5}\right)+i\sin \left(\frac{\pi \:\:}{5}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{3\pi \:}{2}\right)+i\sin \left(\frac{3\pi \:\:}{2}\right)\right]

Now to solve such problems, you will need to know what cos(π / 5) is, sin(π / 5) etc. If you don't know their exact value, I would recommend you use a calculator,

cos(π / 5) = \frac{\sqrt{5}+1}{4},

sin(π / 5) = \frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}

cos(3π / 2) = 0,

sin(3π / 2) = - 1

Let's substitute those values in our expression,

14\left[\frac{\sqrt{5}+1}{4}+i\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}\right]\cdot \:2\sqrt{2}\left[0-i\right]

And now simplify the expression,

14\sqrt{5-\sqrt{5}}+i\left(-7\sqrt{10}-7\sqrt{2}\right)

The exact value of 14\sqrt{5-\sqrt{5}} = 23.27510\dots and (-7\sqrt{10}-7\sqrt{2}\right)) = -32.03543\dots Therefore we have the expression 23.27510 - 32.03543i, which is close to option c. As you can see they approximated the solution.

( 2 ) Here we will apply the following trivial identities,

cos(π / 3) = \frac{1}{2},

sin(π / 3) = \frac{\sqrt{3}}{2},

cos(- π / 6) = \frac{\sqrt{3}}{2},

sin(- π / 6) = -\frac{1}{2}

Substitute into the following expression, representing the quotient of the given values of z1 and z2,

15\left[cos\left(\frac{\pi \:}{3}\right)+isin\left(\frac{\pi \:\:}{3}\right)\right] \div \:3\sqrt{2}\left[cos\left(\frac{-\pi \:}{6}\right)+isin\left(\frac{-\pi \:\:}{6}\right)\right] ⇒

15\left[\frac{1}{2}+\frac{\sqrt{3}}{2}\right]\div  \:3\sqrt{2}\left[\frac{\sqrt{3}}{2}+-\frac{1}{2}\right]

The simplified expression will be the following,

i\frac{5\sqrt{2}}{2} or in other words \frac{5\sqrt{2}}{2}i or \frac{5i\sqrt{2}}{2}

The solution will be option a, as you can see.

6 0
4 years ago
Helphelphelphelphelp​
german

Answer:

Step-by-step explanation:

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6 0
3 years ago
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A recipie calls for 2 3/4 cups of milk.How many cups of milk,written as a fraction greater than one,are used in the recipie
viva [34]
2*4=8+3=11... so 11/4 cups
8 0
4 years ago
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What is the range of f(x) = 3x + 9?
SOVA2 [1]

Step-by-step explanation:

there must be some additional information missing (like the domain of the function), because just as it is written here, the function f(x) would not have any limitations, and its range would be -infinity < y < +infinity.

so, it is impossible to tell you which answer option is correct.

because again, based on the given information, none of these options is correct.

8 0
3 years ago
GUYS PLEASE HELP DUE SOONNN
jek_recluse [69]

Answer: -1 1/2 to -1: -1 1/3 and -5/4

-1 to -1/2: -2/3, -3/4, -6/7, -5/6

-1/2 to 0: -1/3 and -3/8

0 to 1/2: 1/5, 1/10, 3/12, 3/8, 3/7, 1/3

1/2 to 1: 4/5, 6/10, 7/8, 7/9, 3/4, 8/10

1 to 1 1/2: 1 5/12, 9/8

Step-by-step explanation:

4 0
3 years ago
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