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vichka [17]
4 years ago
8

Can somebody explain how trigonometric form polar equations are divided/multiplied?

Mathematics
1 answer:
koban [17]4 years ago
6 0

Answer:

Attachment 1 : Option C

Attachment 2 : Option A

Step-by-step explanation:

( 1 ) Expressing the product of z1 and z2 would be as follows,

14\left[\cos \left(\frac{\pi \:}{5}\right)+i\sin \left(\frac{\pi \:\:}{5}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{3\pi \:}{2}\right)+i\sin \left(\frac{3\pi \:\:}{2}\right)\right]

Now to solve such problems, you will need to know what cos(π / 5) is, sin(π / 5) etc. If you don't know their exact value, I would recommend you use a calculator,

cos(π / 5) = \frac{\sqrt{5}+1}{4},

sin(π / 5) = \frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}

cos(3π / 2) = 0,

sin(3π / 2) = - 1

Let's substitute those values in our expression,

14\left[\frac{\sqrt{5}+1}{4}+i\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}\right]\cdot \:2\sqrt{2}\left[0-i\right]

And now simplify the expression,

14\sqrt{5-\sqrt{5}}+i\left(-7\sqrt{10}-7\sqrt{2}\right)

The exact value of 14\sqrt{5-\sqrt{5}} = 23.27510\dots and (-7\sqrt{10}-7\sqrt{2}\right)) = -32.03543\dots Therefore we have the expression 23.27510 - 32.03543i, which is close to option c. As you can see they approximated the solution.

( 2 ) Here we will apply the following trivial identities,

cos(π / 3) = \frac{1}{2},

sin(π / 3) = \frac{\sqrt{3}}{2},

cos(- π / 6) = \frac{\sqrt{3}}{2},

sin(- π / 6) = -\frac{1}{2}

Substitute into the following expression, representing the quotient of the given values of z1 and z2,

15\left[cos\left(\frac{\pi \:}{3}\right)+isin\left(\frac{\pi \:\:}{3}\right)\right] \div \:3\sqrt{2}\left[cos\left(\frac{-\pi \:}{6}\right)+isin\left(\frac{-\pi \:\:}{6}\right)\right] ⇒

15\left[\frac{1}{2}+\frac{\sqrt{3}}{2}\right]\div  \:3\sqrt{2}\left[\frac{\sqrt{3}}{2}+-\frac{1}{2}\right]

The simplified expression will be the following,

i\frac{5\sqrt{2}}{2} or in other words \frac{5\sqrt{2}}{2}i or \frac{5i\sqrt{2}}{2}

The solution will be option a, as you can see.

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3 years ago
In a survey of 1,003 adults concerning complaints about restaurants, 732 complained about dirty or ill-equipped bathrooms and 38
Ganezh [65]

Answer:

a

0.716  <  p <  0.744

b

0.3498  <  p <  0.4089

c

 With the result obtained from a and b the manager can be 95 % confidence that the proportion of the population that complained about dirty or ill-equipped bathrooms are within the interval obtained at  a

and that

the proportion of the population that complained about loud or distracting diners at other tables are within the interval obtained at  b

Step-by-step explanation:

From the question we are told that

The sample size is  n  =  1003

The number that complained about dirty or ill-equipped bathrooms is e = 732

 The number that complained about loud or distracting diners at other tables is  q =  381

Given that the the confidence level is  95% then the level of significance is mathematically represented as  

         \alpha = (100- 95)\%

         \alpha = 0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table , the value is  

         Z_{\frac{\alpha }{2} } =  1.96

Considering question a

The sample proportion is mathematically represented as

           \r p  =  \frac{e}{n}

=>        \r p  =  \frac{732}{1003}

=>        \r p  =  0.73

Generally the margin of error is mathematically represented as

          E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{ \r p (1- \r p)}{n} }

          E =  1.96*  \sqrt{ \frac{ 0.73 (1- 0.73)}{1003} }

          E = 0.01402

The 95% confidence interval is  

        \r p  -  E  <  p  <  \r p +E

        0.73 - 0.01402 <  p <  0.73 +  0.01402

        0.716  <  p <  0.744

Considering question b

The sample proportion is mathematically represented as

           \r p  =  \frac{q}{n}

=>        \r p  =  \frac{381}{1003}

=>        \r p  =  0.3799

Generally the margin of error is mathematically represented as

          E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{ \r p (1- \r p)}{n} }

          E =  1.96*  \sqrt{ \frac{ 0.3799 (1- 0.3799)}{1003} }

          E = 0.0300

The 95% confidence interval is  

        \r p  -  E  <  p  <  \r p +E

        0.3798 - 0.0300 <  p <  0.3798 + 0.0300

        0.3498  <  p <  0.4089

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3 years ago
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