if the diameter is 26 yards, then its radius is half that, or 13 yards.
![\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=13 \end{cases}\implies C=2\pi (13)\implies C=26\pi \implies C\approx 81.68 \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=13 \end{cases}\implies A=\pi (13)^2\implies A=169\pi \implies A\approx 530.93](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D2%5Cpi%20r~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D13%20%5Cend%7Bcases%7D%5Cimplies%20C%3D2%5Cpi%20%2813%29%5Cimplies%20C%3D26%5Cpi%20%5Cimplies%20C%5Capprox%2081.68%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D13%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2813%29%5E2%5Cimplies%20A%3D169%5Cpi%20%5Cimplies%20A%5Capprox%20530.93)
Statement : If the perpendicular bisectors of two sides of a triangle meet at point that belongs to the third side then this is a right angle triangle.
Prove:
Let ABC is triangle,
In which DF and EF are the perpendicular bisectors of legs AB and BC respectively.
That is, ∠ FDB = ∠BEF= 90°
Where, 
Then By the property of the circumcenter,
F must be mid point of leg AC.
That is, DF ║ BC
⇒ ∠ FDB + ∠ DBC = 180° ( the sum of two adjacent angles on the parallel lines by the same transversal is supplementary )
But, ∠ FDB = 90°
⇒∠ DBC = 90°
⇒ ∠ ABC = 90°
That is, Δ ABC is a right angle triangle.
the answer is -2/5 hope this helped
The answer is 15 because the elevator is moving 15 feet every second :)