Answer:
Please find attached a drawing of the triangles ΔRST and EFG showing the angles
The angle on ΔEFG that would prove the triangles are similar is ∠F = 25°
Step-by-step explanation:
In order to prove that two triangles are similar, two known angles of each the triangles need to be shown to be equal
Given that triangle ∠R and ∠S of triangle ΔRST are 95° and 25°, respectively, and that ∠E of ΔEFG is given as 90°, then the corresponding angle on ΔEFG to angle ∠S = 25° which is ∠F should also be 25°
Therefore, the angle on ΔEFG that would prove the triangles are similar is ∠F = 25°.
Answer:
x = 5
Step-by-step explanation:
As it is parallelogram And we can see the diagonals bisect each other and are divided into equal parts so
2x = 15 - x
2x + x = 15
3x = 15
x = 15 / 3
x = 5
Answer:
1.4b
Step-by-step explanation:
4b-2.6b
4.0-2.6=1.4
4b-2.6b=1.4b
Answer:
-11
Step-by-step explanation:
hope that can help!!
Answer: Distance between parent and coach = 24.05m
Step-by-step explanation:
Angle of sight between the coach and the ground(θ) = 38°
Angle of sight between the parent and the ground (θ) = 30°
Height of diving platform = 10m
The horizontal distance(x) between the coach and Melanie :
Tanθ = opp / adj
Tan 38° = 10 / x
x = 10 / 0.7812856
x = 12.79m
The horizontal distance (y) between the parent and Melanie :
Tanθ = opp / adj
Tan 30° = 10 / y
y = 10 / 0.5773502
y = 17.32m
Angle at base of platform between Melanie's coach and her parent = 105°
Distance (a) between coach and parent can be calculated using the cosine rule.
a^2 = x^2 + y^2 - 2bcCosA
Where a, b, c are side lengths and A is the included angle
Therefore,
a^2 = 12.79^2 + 17.32^2 - 2(12.79)(17.32)Cos105°
a^2 = 163.5841 + 299.9824 − (-114.6686)
a^2 = 163.5841 + 299.9824 + 114.6686
a^2 = 578.2351
a = √578.2351
a = 24.046519
a = 24.05m
