Question

In a sample of 800 people, 420 are in favor of a proposed scoring system. A golf course wants to implement an electronic scoring system where shots are counted by satellites to reduce human error and to show real-time scores at the clubhouse. Is there enough evidence to conclude that the majority of the golfing community is a proponent of the new system at an alpha level of .05. Determine the number of tails for this problem, the critical value and the test statistic.

Answer 1

Answer:

We accept H₀ with 95 % of Confidence Interval we have enough evidence to conclude that the majority of members agree with the new system

Step-by-step explanation:

Sample size      800

Sample   x₁   = 420   ( number of people in favor of a proposed scoring system), then

p₁ = 420/800   p₁  =  0,525    p₁  = 52,5 %  then

q₁  =  1  - p₁     q₁  =  1  - 0,525      q₁  =  0,475

Sample size enought to use the approximation of the binomial didtribution to normal distribution

If significance level is 0,05    α  = 0,05

and from z-table we look for z(c)  ( z critical value)

z (c)  = 1,64

Hypothesis Test:

Null Hypothesis                       H₀            p₁  = 0,5

Alternative Hypothesis           Hₐ            p₁  >  0,5

Alternative hypothesis tells us about a one tail-test to the right

To calculate

z(s) =  (  p₁  -  0,5) / √ (p₁*q₁) / n

z(s) =   0,025 / √ 0,525*0,475/800

z(s) =   0,025 / √0,000311

z(s) = 0,025/0,01765

z(s) = 1,416

Comparing z(c)  and z(s)

z(s) < z(c)       1,416 <  1,64

z(s) is in the acceptance region we accep H₀.