Answer:
9
Step-by-step explanation:
.15/1=x/60
100 • x = 1x
.15 • 60= 9
1x/1=9/1
x=9
Answer:
The probability that all nine references are still good two years later is P(all nine are still good)=0.29.
The assumption we have to make is that the occurrence of the site references in the paper are independent events.
Step-by-step explanation:
The assumptions we have to make about the papers is that their probabilities of survival are independent of each other. This is the same as saying: The occurrence of the site references in the paper are independent events.
The probabilities of survival of any reference is:

The probability of the nine references are still good later can be calculated as:

The probability that all nine references are still good two years later is P=0.29.
Answer:
D
Step-by-step explanation:
if x=5 then,
y=-6×1+11
=-6+11
=5