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astra-53 [7]
3 years ago
5

See question above ^^​

Mathematics
1 answer:
denpristay [2]3 years ago
7 0
I think the answer is (4) because if you rotate AEC to the left (counterclockwise) and follow by the scale factor of 2 so, CE = 4x2 = 8 and CA = 3x2 = 6. Hope this help :))
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Please help!!! Work out the surface area for this solid prism.
zhannawk [14.2K]

Answer:

3060 cm^{2}

Step-by-step explanation:

<u>Find the cross-sectional area first of the trapezium</u>

\frac{1}{2} (a+b)h

So,  \frac{1}{2}(6+34)15

which is 40 / 2 x 15 = 20 x 15 = 300 cm^{2}

Since there are 2 trapeziums (on the front and back): 300 x 2 = 600cm^{2}

<u>Find the Area of the Rectangles</u>

The first rectangle on the top would be: 6x30 = 180 cm^{2}

The slanted rectangle on the right would be: 25x30 = 750 cm^{2}

The rectangle on the bottom would be: 30x34 = 1020 cm^{2}

The hidden rectangle on the left would be: 17 x 30 = 510 cm^{2}

So by combining all these calculations, you will get the total surface area which is:

600 + 180 + 750 + 1020 + 510 = 780 + 1770 + 510 = 2550 + 510 = 3060 cm^{2}

3 0
3 years ago
If point A is located at -8 on a number line and point B is located at 3 what is the distance between the two points?​
Phantasy [73]

Answer:

5

Step-by-step explanation:

you just have to subtract 3 by 8 and then you get 5

4 0
3 years ago
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The diagonals in a kite __________.
joja [24]
B. are perpendicular
5 0
3 years ago
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Please help!!!!!!!!!!!!<br> Will mark brainliest
Sauron [17]

Answer:

○ \displaystyle 25

Step-by-step explanation:

\displaystyle 4 = 2\sqrt{25} - 6 \\ 4 = 2[5] - 6 \\ \\ 4 = 10 - 6

I am joyous to assist you at any time.

3 0
2 years ago
Samples of rejuvenated mitochondria are mutated (defective) in 3% of cases. Suppose 17 samples are studied, and they can be cons
andrey2020 [161]

Answer:

a) 59.58%

b) 90.90%

c) 0%

Step-by-step explanation:

Let p be the probability a sample is mutated. Then q= 1-p is the probability the sample IS NOT mutated.

So <em>p=0.03 (3%) and q=0.97 (97%). </em>

The experiment of finding a mutated sample out of 17 clearly has a binomial distribution, where the probability of finding k mutated samples out of 17 is given by

P(17;k)=\binom{17}{k}(0.03)^k(0.97)^{17-k}

a)  

<em>We want P(17;0)</em>  

P(17;0)=\binom{17}{0}(0.03)^0(0.97)^{17}=(0.97)^{17}=0.5958=59.58\%

b)

<em>We want P(17;0)+P(17;1) </em>

P(17;0)+P(17;1)=0.5958+\binom{17}{1}(0.03)(0.97)^{18}=0.5958+0.3132=0.9090=90.90\%

c)

<em>We want P(17;9)+P(17;10)+...+P(17;17) </em>

Computing this number, we get  

3.8448*10^{-34}

This figure is zero if we round to 2 decimals

7 0
3 years ago
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