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astra-53 [7]
3 years ago
5

See question above ^^​

Mathematics
1 answer:
denpristay [2]3 years ago
7 0
I think the answer is (4) because if you rotate AEC to the left (counterclockwise) and follow by the scale factor of 2 so, CE = 4x2 = 8 and CA = 3x2 = 6. Hope this help :))
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Identify the sampling designs that use voluntary response sampling. Check all that apply.
Marta_Voda [28]

Step-by-step explanation:  

A voluntary response sample is defined as a type of sample made up of self-chosen participants. These participants volunteer to take part in different research studies to share their opinions on topics that interest them. A voluntary response sample is made up of persons who volunteer to take research surveys.

3 0
2 years ago
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If Cos 30° equals rad 3/2 then the sin 60° equals <br><br> a) 0<br> b) 1/2<br> c) rad 3/2<br> d) 1
vovangra [49]

Answer:

c) rad 3/2

Step-by-step explanation:

If Cos 30° equals rad 3/2 then the sin 60° equals rad 3/2.

8 0
3 years ago
There are 20 balls in a bag. Ten of the balls are red, 4 are green, and the rest are yellow.
xxMikexx [17]

Answer:

3/5

Step-by-step explanation:

I took the test

4 0
2 years ago
100 points PLEASE ANSWER ASAP thank you so much
uysha [10]

Answer:

X elevated to 21/25

Step-by-step explanation:

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(3/5)*(7/5) =

21/25

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Regards

7 0
1 year ago
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he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
2 years ago
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