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3 years ago

Plz helppp Do the calculation below 6(18 + 14)

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

8 0

Answer:

Explained below...

Step-by-step explanation:

First, recognize the acronym PEMDAS, which stands for:

P - Parenthesis

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

So, as there are parenthesis, that will be your first step in the expression.

6(18 + 14) --> 6(32)

Now, you will find the next step in PEMDAS, which would be multiplication.

6 * 32 = 192.

So, your answer for the equation is 192.

Hope this helps! :)

levacccp [35]3 years ago

5 0

Answer:

6(18 + 14) = 192

Step-by-step explanation:

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2 years ago

If anyone's good with interquartile range, median, upper quartile, lower quartile stuff, please help ASAP!

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Answer: B, Range is 16, IQR is 7

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Quartiles:

Quartiles mark each 25% of a set of data:

The first quartile Q1 is the 25th percentile

The second quartile Q2 is the 50th percentile

The third quartile Q3 is the 75th percentile

The second quartile Q2 is easy to find. It is the median of any data set and it divides an ordered data set into upper and lower halves. The first quartile Q1 is the median of the lower half not including the value of Q2. The third quartile Q3 is the median of the upper half not including the value of Q2.

How to Calculate Quartiles:

Order your data set from lowest to highest values

Find the median. This is the second quartile Q2.

At Q2 split the ordered data set into two halves.

The lower quartile Q1 is the median of the lower half of the data.

The upper quartile Q3 is the median of the upper half of the data.

If the size of the data set is odd, do not include the median when finding the first and third quartiles. If the size of the data set is even, the median is the average of the middle 2 values in the data set. Add those 2 values, and then divide by 2. The median splits the data set into lower and upper halves and is the value of the second quartile Q2.

How to Find Interquartile Range

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How to Find the Minimum:

The minimum is the smallest value in a sample data set.

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2 years ago

Starting with 10 blue balls, in each of 10 sequential rounds, we remove a random ball and replace it with a new red ball. For ex

s344n2d4d5 [400]

Answer:

Suppose the fraction of blue balls at any given state n is $f_{n}$ . At the start of the process we have: $f_{0}$ =1.

Now consider the situation after having drawn n times.

The current fraction of blue balls is $f_{n}$ , the number of blue balls is therefore 10 $f_{n}$ .

We either draw a red ball, with probability 1− $f_{n}$ . and the number of red balls, blue balls stay the same (we swap red for red):

$f_{n+1}$ (red)= $f_{n}$

or we draw a blue ball, with probability $f_{n}$ and we obtain 10 $f_{n}$ −1 blue balls on a total of 10 balls, thus:

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The total probability of (fraction of) blue balls after this n'th draw is therefore:

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At the end of the 10'th draw the fraction of blue balls is equal to:

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3 years ago