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3 years ago

6

Please hurry Simplify. Enter the answer in the box.

a1" title=" \sqrt{1.21} " alt=" \sqrt{1.21} " align="absmiddle" class="latex-formula">

2 answers:

givi [52]3 years ago

6 0

First of all you need to find what number squared gives 1.21
So to make it easier first you find which number squared gives 121, ( you simply multiply 1.21 by 100)
After you find that number which is 11 you got to divide it by 10( since 10 square is 100)
The final answer is 1.1

Nat2105 [25]3 years ago

4 0

Answer:

the answer is 3

15/(2+3)

=15/5

=3

Step-by-step explanation:

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Practice question — Given the trapezoid to the right find the length of legs in the following isosceles trapezoid

ad-work [718]

Given:

A figure of an isosceles trapezoid with bases 18 and 24, and the vertical height is 4.

To find:

The legs of the isosceles trapezoid.

Solution:

Draw another perpendicular and name the vertices as shown in the below figure.

From the figure it is clear that the AEFD is a rectangle. So,

$EF=AD=18$

Since ABCD is an isosceles trapezoid, therefore in triangle ABE and DCF,

$AB=DC$ (Legs of isosceles trapezoid)

$AE=DF$ (Vertical height of isosceles trapezoid)

$m\angle AEB=m\angle DFC$ (Right angle)

$\Delta ABE\cong \Delta DCF$ (HL postulate)

$BE=CF$ (CPCTC)

Now,

$BE+EF+FC=BC$

$2BE+18=24$

$2BE=24-18$

$2BE=6$

$BE=3$

Using Pythagoras theorem in triangle ABE, we get

$Hypotenuse^2=Perpendicular^2+Base^2$

$(AB)^2=(AE)^2+(BE)^2$

$(AB)^2=(4)^2+(3)^2$

$(AB)^2=16+9$

$(AB)^2=25$

Taking square root on both sides, we get

$AB=\pm \sqrt{25}$

$AB=\pm 5$

Side length cannot be negative. So, $AB=5$ .

Therefore, the length of legs in the given isosceles trapezoid is 5 units.

3 0

3 years ago

The voltage across the capacitor increases as a function of time when an uncharged capacitor is placed in a single loop with a r

dmitriy555 [2]

Answer:

1. Exponential

Step-by-step explanation:

The simplest RC-Circuit, that is, a capacitor and a resistor in a series configuration can be modeled by using Ohm's Law and Kirchhoff's Circuit Laws:

$C \cdot \frac{dV}{dt} + \frac{V}{R} = 0$

By rearranging the formula, an homogeneous linear first-order differential equation is found:

$\frac{dV}{dt} + \frac{1}{R \cdot C} \cdot V = 0$

Whose solution has the form of a exponential model:

$V(t) = V_{o} \cdot e^{-\frac{t}{R \cdot C} }$

7 0

3 years ago

How are the lengths of the four sides of the parallelogram related ?

goldfiish [28.3K]

Answer:

Step-by-step explanation: Opposite sides of a parallelogram are equal.

3 0

3 years ago

Read 2 more answers

Find the greatest common factor of 7 and 21.

sertanlavr [38]

Answer: 7

Step-by-step explanation:

Factors of 7 are, 1, and 7. The factors of 21 are, 1, 3, 7, and 21, making 7 the gcf.

6 0

3 years ago

Insert two geometric means between 729 and 64

Liula [17]

Answer:

324 and 144

Step-by-step explanation:

We require

a₁, a₂, a₃, a₄

where a₂ and a₃ are the required geometric means

The n th term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 729 and a₄ = 64, thus

729(r³) = 64 ( divide both sides by 729 )

r³ = $\frac{64}{729}$ ( take the cube root of both sides )

r = $\sqrt[3]{\frac{64}{729} }$ = $\frac{4}{9}$ , then

a₂ = 729 × $\frac{4}{9}$ = 81 × 4 = 324

a₃ = 324 × $\frac{4}{9}$ = 36 × 4 = 144

Thus

729, 324, 144, 64

8 0

3 years ago