For the process of transformation of glucose into pyruvate, NAD⁺ is converted into NADH. These same NADH molecules are then reutilised on the pyruvate to lactic acid reaction and are therefore transformed back into NAD⁺ molecules that will again be used for another glycolysis reaction.
From the first rectangle, on the left, to the last rectangle, on the right, it comes NAD⁺ - NADH - NADH - NAD⁺.
Options for the question have not been given. They are as follows:
A) 1/8
B) 3/4
C) 1/16
D) 1/2
Answer:
D) 1/2
Explanation:
Let the allele for extra digits be represented by D. Since it is a dominant trait, DD and Dd will result in extra digits whereas dd will result in normal number of digits. The woman has normal number of digits so she has dd genotype. The man has extra digits so he can be either DD or Dd.
The couple's first child has normal number of digits so she has dd genotype. She has obtained one d allele from her mother and another d allele from her father. Hence, the man's genotype is Dd.
Man = Dd
Woman = dd
Their children :
D d
d Dd dd
d Dd dd
Half of the progeny will have Dd genotype and will have extra digits. Other half will have dd genotype and will have normal number of digits. So, the probability of their next child to have extra digits is 1/2.
They are in response to the environment. Both are homoeostatic mechanisms that lower the core temperature of the body in response to an increase in body temperature. This is an example of 'negative feedback'.
I believe it is called <span>heterozygous. Hope this helped! </span>
It is true that a<span>n ecologist who is studying the relationships among the dominant communities in a geographical region is studying a biome.
A biome is a group of ecosystems that have the same climate and similar dominant communities, so you can see that the answer to this question is T.</span>
