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olchik [2.2K]
3 years ago
6

Which set of ordered pairs contains only points that are on the graph of the function y=12-3×?

Mathematics
1 answer:
irina [24]3 years ago
8 0
Y= 12 -3x so if you take x as 0 y=12 x=1 y=9 x=2 y=6

(0, 12) (1,9), (2,6) are on the graph
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Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)>0
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The answer is x<2
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Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~​
Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

\sf\longrightarrow sin^2\theta + cos^2\theta = 1

Imagine a right angled triangle with one of its acute angle as \theta .

  • The side opposite to this angle will be perpendicular .
  • Also we know that ,

\sf\longrightarrow sin\theta =\dfrac{p}{h} \\

\sf\longrightarrow cos\theta =\dfrac{b}{h}

And by Pythagoras theorem ,

\sf\longrightarrow h^2 = p^2+b^2 \dots (i)

Where the symbols have their usual meaning.

Now , taking LHS ,

\sf\longrightarrow sin^2\theta +cos^2\theta

  • Substituting the respective values,

\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\

\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\

\sf\longrightarrow \dfrac{p^2+b^2}{h^2}

  • From equation (i) ,

\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\

\sf\longrightarrow \bf 1 = RHS

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0
2 years ago
Can someone help me with this problem. I don’t know how to do volume.
densk [106]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Korvikt [17]

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Step-by-step explanation:

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6 0
3 years ago
What is the rule of a function of the form f(t)= a sin (bt+c) +d whose graph appears to be identical to the given graph?
olasank [31]

Answer:

Option A.

f(x) = -4*sin((1/3)*t + (π/6))  + 3

Step-by-step explanation:

We can easily solve this problem by using a graphing calculator or plotting tool.

The function is

f(t) = a*sin (b*t +c) + d

Please, see attached picture below.

By looking at the picture with all the possible cases, we can tell that the correct option is A.

The function has a period of T = 6π

Max . Amplitude = 7

Min . Amplitude = -1

7 0
2 years ago
Read 2 more answers
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