Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Answer:
≈ 35.1 ft
Step-by-step explanation:
The model is a right triangle with ladder being the hypotenuse and the angle between the ground and the ladder is 70°
Using the cosine ratio, with l being the length of the ladder.
cos70° = 
= 
( multiply both sides by l )
l × cos70° = 12 ( divide both sides by cos70° )
l = 
≈ 35.1 ( to the nearest tenth )
The ladder is approx 35.1 ft long
<span>0.4x + 6.1 = 0
0.4x = - 6.1
x = - 6.1 / 0.4
x = - 15.25</span>
Answer:
B. y= 1/2 x - 3
Step-by-step explanation:
base equation: y= mx+ b
slope(m) equation: 
y2= -1 y1= -3
x2= 4 x1= 0
y- intercept: -3
found by taking the y from (0,-3)
I would say
Balanced forces result in constant velocity: phase 3
Unbalanced force causes change in velocity: phase 4
The more unbalanced the forces are, the greater the changes in velocity is: phase 5
Hope this helps
