A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
Step-by-step explanation: The area of the bedroom is
A=7yd^2
The total cost is the sum of the price rates times this area.
C=A•($21+$5)/yd^2
where C is total cost.
C=7yd^2•($21+$5)/yd^2
C=$182
Answer:
30 three-pointers
Step-by-step explanation:
if u need explanation, lmk and i'll type it in the comments to this question.
The answer is Triangle PQR
Answer:
a: K = 2s
K + s = 42
b: 2s + s = 42
K = 28
s = 14
Step-by-step explanation:
1. Come up with equations based on the information given.
K = Kim
s = sister
Kim is twice of her sister -> K = 2s
When you add Kim's age to her sister's age, you get 42 -> K + s = 42
2. Substitue for K to find out the value of s
K = 2s
2s + s = 42
3. Solve for s
s = 42/3
s= 14
4. Solve for K
K = 2s
K = 2*14
K = 28
