To answer the problem above, we first need to know the difference in hours.
from month 1 to 2 the difference in hour is 1.5.
Month 2 to 3 = 3.5 to 5 = 1.5
Month 3 to 4 = 5 to 6.5 = 1.5
Month 4 to 5 = 6.5 to 8 = 1.5
The answer is C. Linearly, because the table shows that hours increase by an equal factor for an equal increase in months. which is 1.5 hours per month.
Answer:
fjvg8rg95ig9tjbopetjihefgiuo ugn idgjbiohionuion ijj ngibj irogjk0 krlkntirion pohtk ioh ht nh h h h h h
Step-by-step explanation:
Answer:
Step-by-step explanation:
B(2,10); D(6,2)
Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)
Rhombus all sides are equal.
AB = BC = CD =AD
distance = √(x2-x1)² + (y2- y1)²
As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x
A(X,0)
AB = AD
√(2-x)² + (10-0)² = √(6-x)² + (2-0)²
√(2-x)² + (10)² = √(6-x)² + (2)²
√x² -4x +4 + 100 = √x²-12x+36 + 4
√x² -4x + 104 = √x²-12x+40
square both sides,
x² -4x + 104 = x²-12x+40
x² -4x - x²+ 12x = 40 - 104
8x = -64
x = -64/8
x = -8
A(-8,0)
Let C(a,b)
M is AC midpoint
(-8+a/2, 0 + b/2) = M(4,6)
(-8+a/2, b/2) = M(4,6)
Comparing;
-8+a/2 = 4 ; b/2 = 6
-8+a = 4*2 ; b = 6*2
-8+a = 8 ; b = 12
a = 8 +8
a = 16
Hence, C(16,12)
