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kvasek [131]
3 years ago
11

Pleaseeee helpppp !!!!!!!!! Will mark Brianliest !!!!!!!!!!!

Mathematics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

KL = 50

Step-by-step explanation:

∆JML is similar to ∆JNL. it follows that:

[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]

JM = 4 + 20 = 24

JN = 4

JL = 10 + KL

JK = 10

Plug in the values

[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]

[tex] 6 = \frac{10 + KL}{10} [\tex]

Multiply both sides by 10

[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]

[tex] 60 = 10 + KL [\tex]

Subtract 10 from each side

[tex] 60 - 10 = KL [\tex]

[tex] 50 = KL [\tex]

KL = 50

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Answer:

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Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, H_0 : p_1 = p_2 {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

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The test statistics used here will be two sample Binomial statistics i.e.;

                             \frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } } ~ N(0,1)

Here, \hat p_1 = No. of students passed the exam ÷ No.of Students that had taken the course

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P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

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