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2 years ago

What is the vertex of f(x)=(x-8)(x-2)

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

5 0

Hello!

To find the vertex of f(x), we can simplify this function into standard form.

f(x) = (x - 8)(x - 2)

f(x) = x² + -10x + 16

With the equation in standard form, we use the formula: x = -b/2a. Then, we substitute the value of x into the equation to solve for the y-value.

x = -(-10) / 2(1)

x = 10 / 2

x = 5

Then, we substitute x = 5 into the original equation.

f(x) = (5 - 8)(5 - 2)

f(x) = -3(3)

f(x) = -9

Therefore, the vertex of f(x) is (5, -9).

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Alona [7]

Given:

One linear function represented by the table.

Another linear function represented by the graph.

To find:

The greater unit rate and greater y-intercept.

Solution:

Formula for slope (unit rate):

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the given table it is clear that the linear function passes through (0,5) and (5,15). The function intersect the y-axis at (0,15), so the y-intercept is 15.

$m_1=\dfrac{15-5}{5-0}$

$m_1=\dfrac{10}{5}$

$m_1=2$

So, the unit rate of first function is 2.

From the given graph it is clear that the linear function passes through (0,6) and (-4,0). The function intersect the y-axis at (0,6), so the y-intercept is 6.

$m_2=\dfrac{0-6}{-4-0}$