Answer:
It's B I just did it
Step-by-step explanation:
The equation that represents the line that is perpendicular is
3y + 5x = -42
The standard equation of a line in point-slope form is expressed as:

- m is the slope of the lne
- (x1, y1) is any point on the line.
- Given the equation y = 3/2x + 1, the slope of the line is 3/5
- The s<u>lope of the line perpendicular</u> is -5/3
Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

Hence the equation that represents the line that is perpendicular is
3y + 5x = -42
Learn more on equation of a line here:brainly.com/question/19417700
As you can see, in the table of the first function, f(2) = 18, and in the table of the second function g(2) = 18. Then, for x = 2, f(x) = g(x). and x =2 is the solution of the equation.
Answer: x = 2.
For this case we must solve the following equation:

We apply distributive property on the right side of the equation:

We subtract 6y on both sides of the equation:

We subtract 6 from both sides of the equation:

Dividing by 6 on both sides of the equation:

So, the result is 
Answer:

For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>