3 years ago

Compare these two functions, where the input variable represents days.

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

Answer:

c.) 70

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Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

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$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
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-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
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\textit{they're, kinda, except that, when x = 1}
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Explanation: