Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
Lets try to solve out the problem,
Length = 3x-1
Width = x+1
Perimeter = 2(l+b)
Area = l*b
Perimeter= 2 (3x-1 + x+1)
P= 8x
Area = (3x-1) (x+1)
=> 3x(x+1) -1 (x+1)
=> 3x^2 + 3x -x -1
=> 3x^2 + 2x -1.
Hence Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
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Answer:
3.568 < 3.577
Step-by-step explanation:
3.568 < 3.577
So 3.577 is greater than 3.568
Answer:
1
Step-by-step explanation:
5/7+2/7 add the numerator to equal 7/7 simplify to 1/1 equals 1
Answer:
1/2 over 7/8
Step-by-step explanation:
becauseim smartt
Answer:
number 4/ the one that is in the bottom right corner. Thanks for the 100 pts.
pls rate best. God bless!
Step-by-step explanation: