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Serggg [28]
3 years ago
7

PLEASE PLEASE PLEASE HELP ME PLEASE!!

Mathematics
1 answer:
Tatiana [17]3 years ago
6 0

Answer:

x=14 to make the pay equal.

Step-by-step explanation:

Okay so what I did here is kind of time-consuming and I'm sure there's a better way, but I used a calculator to substitute a lot of different numbers into the equation to make it equal, and when I got to 14, the equations both ended up as 625.

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M is directly proportional to r2.when r=2,m=14.Work out the value of m when r=12
valentinak56 [21]

Answer:

504

Step-by-step explanation:

In the attached file

Hope it helps

4 0
4 years ago
Which inequalities is -5 a possible solution?
coldgirl [10]

Answer:

1st, 3rd and second last one

5 0
2 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
Help me please I don't want to fail:)
AysviL [449]

Answer:

the answer is c.768

Step-by-step explanation:

5 0
3 years ago
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in a survey, 250 adults and children were asked whether they know how to swim. the surgery data are shown in the relative freque
Nadusha1986 [10]

Answer: D

Step-by-step explanation:

7 0
2 years ago
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