We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!
We are given with ;
Take LCM on both sides :
<em>Multiplying</em> both sides by <em>10</em> ;
![{:\implies \quad \sf 165+6y=7y+150}](https://tex.z-dn.net/?f=%7B%3A%5Cimplies%20%5Cquad%20%5Csf%20165%2B6y%3D7y%2B150%7D)
Can be <em>further written</em> as ;
Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>
![{:\implies \quad \sf 7y-6y=165-150}](https://tex.z-dn.net/?f=%7B%3A%5Cimplies%20%5Cquad%20%5Csf%207y-6y%3D165-150%7D)
![{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}](https://tex.z-dn.net/?f=%7B%3A%5Cimplies%20%5Cquad%20%5Cbf%20%5Ctherefore%20%5Cquad%20%5Cunderline%7B%5Cunderline%7By%3D15%7D%7D%7D)
Answer:
q = 26
Step-by-step explanation:
Given the point (3, q ) lies on the line then the coordinates satisfy the equation.
Substitute x = 3, y = q into the equation
q = 8(3) + 2 = 24 + 2 = 26
Answer:i dont know
ok
i just need points
Step-by-step explanation:
done ??
So for you’r question its definitely B
Jocks off edi I am British ba da way fanks luvs