Use the elimination method to solve the system of equations. Choose the correct ordered pair
1 answer:
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Answer:
When the volume of a gas in a container varies inversely with the pressure on the gas and a container of nitrogen has a volume of 29.5 litres with 2000 psi. So, if the tank has a 14.7 psi pressure, then the volume of the tank would be 4013.6 litres.
Step-by-step explanation:
- The volume of a gas in a container varies inversely with the pressure on the gas. If a container of nitrogen has a volume of litres with psi, what is the volume if the tank has a psi pressure.
- Calculate the volume to the nearest whole number.
- Use the given values and calculate the proportionality constant as well as required solution.
Step 1 of 2
Write the inversely proportionality relation between the volume and pressure of a gas in container.
Where volume is represented by v and pressure is represented by p.
Remove the proportionality and place a constant say k.
Substitute the given values of nitrogen that v=29.5 and
p=2000 and calculate the value of k from above equation.
Step 2 of 2
Substitute the value p=14.7 and above calculated k value in the equation
The bearing of the tree from Q is 296.565°
<h3>How to determine the height of the tree?</h3>The figure that illustrates the bearing and the distance is added as an attachment
The given parameters are:
Base of the tree, b = 50 meters
Angle (x) = 32 degrees
Calculate the height (h) of the tree using:
tan(x) = height/base
So, we have:
tan(32°) = h/50
Make h the subject
h= 50 × tan(32°)
Evaluate
h = 31.24
Hence, the height of the tree is 31.24 meters
<h3>How to determine the distance between Q and the base of the tree?</h3>The distance (d) between Q and the base of the tree
This is calculated using the following Pythagoras theorem
d = √(100² + 50²)
Evaluate
d = 111.80
Hence, the distance between Q and the base of the tree is 111.80 meters
<h3>How to determine the angle of elevation?</h3>The angle of elevation (x) using the following tangent trigonometric ratio
tan(x) = h/d
This gives
tan(x) = 31.24/111.80
Evaluate the quotient
tan(x) = 0.2794
Take the arc tan of both sides
x = 15.61
<h3>The bearing of the tree from Q </h3>This is calculated using:
Angle of bearing = 270 + arctan(50/100)
Evaluate the arc tan
Angle of bearing = 270 + 26.565
Evaluate the sum
Angle of bearing = 296.565
Hence, the bearing of the tree from Q is 296.565 degrees
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