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Elza [17]
2 years ago
8

Can someone please help me solve the following?​

Mathematics
1 answer:
mestny [16]2 years ago
8 0

Answer try caculator soup it has so many diff calulators

Step-by-step explanation:

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#18)  (√2)/(2y)
#19)  7x/5
#20)  (2√5)/5
#21)  (3√5)/5
#22)  √5/b
#23)  (2√(2n))/n
#24)  (2√15)/15m

For #18:
\sqrt{\frac{18y}{36y^3}}=\sqrt{\frac{1}{2y^2}}=\frac{1}{y\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2y}

#19:
\sqrt{\frac{49x^5}{25x^3}}=\sqrt{\frac{49x^2}{25}}=\frac{7x}{5}

#20:
\frac{\sqrt{12}}{\sqrt{15}}=\frac{2\sqrt{3}}{\sqrt{15}}\times \frac{\sqrt{15}}{\sqrt{15}}=\frac{2\sqrt{45}}{15}=\frac{6\sqrt{5}}{15}=\frac{2\sqrt{5}}{5}

#21:
\frac{\sqrt{72}}{\sqrt{40}}=\frac{6\sqrt{2}}{2\sqrt{10}}=\frac{3\sqrt{2}}{\sqrt{10}}\times \frac{\sqrt{10}}{\sqrt{10}}=\frac{3\sqrt{20}}{10}=\frac{6\sqrt{5}}{10}=\frac{3\sqrt{5}}{5}

#22:
\sqrt{\frac{25b}{5b^3}}=\sqrt{\frac{5}{b^2}}=\frac{\sqrt{5}}{b}

#23:
\sqrt{\frac{24}{3n}}=\sqrt{\frac{8}{n}}=\frac{2\sqrt{2}}{\sqrt{n}}\times \frac{\sqrt{n}}{\sqrt{n}}=\frac{2\sqrt{2n}}{n}

#24:
\sqrt{\frac{8}{30m^2}}=\sqrt{\frac{4}{15m^2}}=\frac{2}{m\sqrt{15}}\times \frac{\sqrt{15}}{\sqrt{15}}=\frac{2\sqrt{15}}{15m}
3 0
4 years ago
6. What is the volume of the Regular Size popcorn? (2 points)<br> Base of 3x5 in and height of 8in
wel
187 is your answer hope it helps
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3 years ago
The sixth graders have a math test and science test today. They have a science test every 9 schools days and a math test every 6
Leokris [45]
In 18 days because the LCM of the two is 18.
8 0
3 years ago
Daniel's print shop purchased a new printer for $35,000. Each year it depreciated at a rate of 5%. What will it's approximate va
Charra [1.4K]

Answer:

dab is cool and fun noice

6 0
3 years ago
Read 2 more answers
a student invested $10,000 received an inheritance in three parts. with one person she brought mutual funds that offered and ret
natka813 [3]

Answer:

The amount invested at 4% per year was $3,000

The amount invested at 4.5% per year was $6,000

The amount invested at 2.5% per year was $1,000

Step-by-step explanation:

Let

x -----> the amount invested at 4% per year

2x ----> the amount invested at 4.5% per year

10,000-3x -----> the amount invested at 2.5% per year

we know that

The interest earned by the amount invested at 4% per year plus the interest earned by the amount invested at 4.5% per year plus the interest earned by the amount invested at 2.5% per year must be equal to $415

so

4\%=4/100=0.04

4.5\%=4.5/100=0.045

2.5\%=2.5/100=0.025

0.04x+0.045(2x)+0.025(10,000-3x)=415

Solve for x

0.04x+0.09x+250-0.075x=415

0.055x=415-250

0.055x=165

x=\$3,000

therefore

The amount invested at 4% per year was $3,000

The amount invested at 4.5% per year was $6,000

The amount invested at 2.5% per year was $1,000

3 0
3 years ago
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