L^2 = 55^2 - 27^2
L^2 = 3025 - 729
L^2 = 2296
L = sqrt(2296) = 47.92 inches
perimeter = 27*2 + 47.92*2 = 54 + 95.84 = 149.84 inches
2(a) 6a-2b+5
2(b) 6x+3y+3z
3. x-2
(Could you tell me the question of the first part pls)
Answer:
36
Step-by-step explanation:
is made up of s + r, and since r is
of
we know r must be the remaining
of
.
We can solve for
by using this equation:

1. 2 fifths of
is 24
2. multiply both sides by
to isolate 
3.
is 60°
We can now solve for r

1. the equation the problem gave us
2. substitute
for 60 (we solved for it before)
3.
is 36°
Answer:
0.8919 = 89.19% probability of filling a cup between 33 and 35 ounces.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A soft drink machine outputs a mean of 29 ounces per cup. The machine's output is normally distributed with a standard deviation of 4 ounces.
This means that 
What is the probability of filling a cup between 33 and 35 ounces?
This is the p-value of Z when X = 35 subtracted by the p-value of Z when X = 33.
X = 35



has a p-value of 0.9332.
X = 33



has a p-value of 0.0413.
0.9332 - 0.0413 = 0.8919
0.8919 = 89.19% probability of filling a cup between 33 and 35 ounces.
3 km is equal to 300000 centimeters0