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maksim [4K]
2 years ago
10

13 added to the product of an integer and negative 7 is 62

Mathematics
1 answer:
lutik1710 [3]2 years ago
5 0

Answer:

Step-by-step explanation:

(x*-7)+13 = 62

(x*-7) = 62 - 13

x*-7 = 49

x = 49 / -7

x = -7

check work

((-7)*-7)+13 = 62

(49)+13 = 62

62 = 62

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What is the slope of line PQ?
Anit [1.1K]

Answer:

Step-by-step explanation:

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by the formula,

Slope = \frac{y_2-y_1}{x_2-x_1}

Slope of the line PQ passing through the two points P(-8, 2) and Q(4, 2) will be,

Slope 'm_1' = \frac{2-2}{-8-2} = 0

Therefore, slope of the line PQ parallel to the x-axis = 0

Slope of the line MN passing through the points M(8, 6) and N(8, -8) is,

Slope 'm_2' = \frac{6+8}{8-8} = ∞

Therefore, slope of the line MN parallel to y-axis is undefined.

Since, angle between the x-axis and y-axis is 90°,angle at the intersection  point between the lines parallel to x and y axis will be 90°.

These lines are perpendicular to each other.

4 0
3 years ago
What is the equation of the line that passes through the point (6,−4) and has a slope of -1/6
Luda [366]

Answer:

y + 4 = (-1/6)(x - 6)

Step-by-step explanation:

Apply the point-slope formula here:  y - k = m(x - h) becomes

y + 4 = (-1/6)(x - 6)

6 0
3 years ago
A room measures 12 feet by 16 feet long. what is the square footage of this room
Leno4ka [110]
12 x 16 = 192. So, the room is 192 square feet.
7 0
3 years ago
Read 2 more answers
What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)
Pani-rosa [81]

perpendicular lines have a slope that is a negative reciprocal


A) 4x-5y=5

subtract 4x

solve for y

-5y = -4x+5

divide by -5

y = 4/5 x+5   slope is 4/5  perpendicular slope is -5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = -5/4 (x-5)

B)  5x+4y = 37

subtract 5x

4y =-5x +37

divide by 4

y =-5/4 x +37/4  slope is -5/4 perpendicular slope is 4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = 4/5 (x-5)

C)4x+5y=5

subtract 4x

5y = -4x +5

divide by 5

y = -4/5 x +1

y =-4/5 x +1  slope is -4/5 perpendicular slope is 5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = 5/4 (x-5)

D)5x-4y=8

subtract 5x

-4y = -5x+8

divide by -4

y = 5/4 x-2

y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = -4/5 (x-5)



6 0
3 years ago
Someone plsss help me quick
Marina CMI [18]

Answer:

15b + 30

Step-by-step explanation:

By expansion (6 x 2.5b) + (6 x 5)

= 15b + 30

5 0
3 years ago
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