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3 years ago

13

When hourly employees work beyond 40 hours in a week, federal law requires that they receive __________ pay. A. commissioned B.

exempt C. overtime D. salaried Please select the best answer from the choices provided A B C D

2 answers:

Zolol [24]3 years ago

3 0

Answer: D

Step-by-step explanation:

vova2212 [387]3 years ago

3 0

Answer:

Answer: D

Step-by-step explanation:

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7 > -4 subtract from both sides<br>I don't get this question plz help..

11Alexandr11 [23.1K]

You need to subtract 7 from both sides, is how I'm interpreting it. So 0>-11

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4 years ago

Find the slope of the line that passes through the points (2, 1) and (-4, -5). -1 1 7/5

Mice21 [21]

The answer is 1.

Use the slope formula to solve.

m= $\frac{y2-y1}{x2-x1}$

Substitute the corresponding values into the equation.

m= $\frac{-5-1}{-4-2}$

m= $\frac{-6}{-6}$

m=1

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3 years ago

Read 2 more answers

The area of a rectangular field is given by the trinomial t2 – 4t – 45. The length of the rectangle is t + 5. What is the expres

aniked [119]

The answer is: width = t - 9

A = l * w
A = t² - 4t - 45
l = t + 5
t² - 4t - 45 = (t + 5)w

$w= \frac{ t^{2} - 4t - 45}{t + 5} = \frac{t * t - 9t + 5t - 5 * 9}{t+5} = \frac{t(t - 9) + 5(t - 9))}{t+5} = \frac{(t-9)(t+5)}{t+5} =t-9$

7 0

3 years ago

Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

4 years ago

I need help please I need help right now ????

katrin [286]

Answer:

x ≈ 36.1

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan61° = $\frac{opposite}{adjacent}$ = $\frac{x}{20}$ ( multiply both sides by 20 )

20 × tan61° = x , then

x ≈ 36.1 ( to the nearest tenth )

6 0

3 years ago