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3 years ago

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Find the slope of the line that passes through the points (2, 1) and (-4, -5). -1 1 7/5

2 answers:

svetoff [14.1K]3 years ago

8 0

Answer:

1

Step-by-step explanation:

Mice21 [21]3 years ago

6 0

The answer is 1.

Use the slope formula to solve.

m= $\frac{y2-y1}{x2-x1}$

Substitute the corresponding values into the equation.

m= $\frac{-5-1}{-4-2}$

m= $\frac{-6}{-6}$

m=1

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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago

Find the value of 5 ∙ 23.

GREYUIT [131]

5 * 23 is equal to 115. =)

4 0

3 years ago

there are 150 more passenger cars than trucks on the highway. for every 10 passenger cars there are 7 trucks. how many trucks ar

lora16 [44]

Answer:

500

Step-by-step explanation:

Given: P = 150 - T where P is passenger cars and T is trucks

10P = 7T ⇔ P = $\frac{7T}{10}$

Plug in equation 2 into equation 1:

$\frac{7T}{10}$ = 150 - T

Solving for T, we get 500

5 0

3 years ago

Read 2 more answers

Which of the following changes will always be true for an exothermic process?

Ivenika [448]

Given that I no not see any explanation in the previos answer, I think you can benefit of this.

Exothermic refers only to the fact that the reaction releases energy in the form of heat when occurs. So, the enthalpy is higher at start and lower and the end.

Seen in this way, you can deduct that the change in enthalpy is negative, which is what the third option says.

6 0

3 years ago

Read 2 more answers

Lynn wants to multiply 44 × 305. She says that all she has to do is find 4×305 and then double that number.

Lubov Fominskaja [6]

Answer C is correct because 2×(4×305) is the same as (2×4)×305 and 2×4=8.

5 0

3 years ago