3(2x+8)=8x+46
6x+24=8x+46
-2x+24=46
-2x=22
x=-11
3(2(-11)+8)=8(-11)+46
3(-22+8)=-88+46
3(-14)=-42
-42=-42
Hope I didn't mess up for your sake
Answer:
-3
Step-by-step explanation:
consider f(x)=y
y=-3x+7
compare with y=mx+c
slope m=-3
Answer:
Step-by-step explanation:
6x
Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.
