Answer:
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy
Step-by-step explanation:
(9xy^2 + 12x^3y^4 − 6x) ÷ 3x = 4x^2y^4 + 3y^2 − 2 (False: 9xy^2:3x=3y^2)
25x^4y^2 + 10x^2y^4 − 15y) ÷ 5y = 5x^4y + 2x^3y^2 − 3 (False: 10x^2y^4:5y=2x^2y^3)
(16x^4y^2 + 24x^2y^2 − 8xy^2) ÷ 4xy = 4x^4y + 6xy− 2y(False: 16x^4y^2:4xy=4x^3y)
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy (True)
6. One variable only so pretty straightforward.
length-x+4
width-x
x+x+4=80
2x=76
x=38
x+4=42
answer: length 42cm and width 38cm
7. Another money problem!
n-# of nickels
q-# of quarters
n=3+q
0.05n+0.25q=2.85
Substitution works like a charm!
0.05(3+q)+0.25q=2.85
0.15+0.05q+0.25q=2.85
0.3q=2.7
q=9
n=3+q
n=3+9
n=12
answer: 9 nickels and 12 quarters
8. One variable situation again.
Ann's money-2b+9
Betty's money-b
b+2b+9=60
3b=51
b=17
2b+9=43
answer: Ann has $43 and Betty has $17.
9. # of red m&m's-x+1
# of blue m&m's-x
x+1+x=13
x=6
x+1=7
answer: 6 blue and 7 red m&m's
10. a-number of adult tickets
s-number of student tickets
a+s=785 ----> a=785-s
5a+2s=3280
5(785-s)+2s=3280
-3s=-645
s=215
a+s=785
a+215=785
a=570
answer: 215 children tickets and 570 adult tickets
Answer:
Hello,
Answer C
Step-by-step explanation:
Since ln(1)=0
if x=1 then y=4 ==> <u>y=ln(x)+4</u>
y=ln(x) is translated up for 4 units.
Answer:
Step-by-step explanation:
<em>Note all arguments of trigonometric functions are in degrees.</em>
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Since tan(35)=4/(longer dotted leg of the triangle), the length of this longer dotted leg is thus 4/tan(35).
Since A=bh, the area is (4/tan35)(12), and you can just plug this into a calculator.
