We choose a 4-digit number randomly. What is the probability that all its digits are even? help asap
2 answers:
Answer:
It's very simple. In 4 decimal digits there are 10,000 (0000 to 9999) possible values. The odds of any one of them coming up randomly is one in 10,000. A specific "4 digit number" would have 1/9000 chance, since there are 9000 4 digit numbers (1000-9999).
Step-by-step explanation:
There are 9,000 true 4 digit numbers and out of that 1000 numbers are divisible by 9.
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Answer:
This is a Right Triangle
Step-by-step explanation:
12=a 16=b 20=c
Now lets solve
a^2+b^2=c^2
144+b^2=c^2
144+256=c^2
144+256=400
c^2=400
The square root of 400 is 20..
This IS a Right Triangle
V = PI x r^2 x h/3
Assume N students
1.)
about 2 minutes
hope this helps
