We choose a 4-digit number randomly. What is the probability that all its digits are even? help asap
2 answers:
Answer:
It's very simple. In 4 decimal digits there are 10,000 (0000 to 9999) possible values. The odds of any one of them coming up randomly is one in 10,000. A specific "4 digit number" would have 1/9000 chance, since there are 9000 4 digit numbers (1000-9999).
Step-by-step explanation:
There are 9,000 true 4 digit numbers and out of that 1000 numbers are divisible by 9. The probability is given by Favourable Possibilities divided by Total Possibilities. In the current case, the probability that the number is divisible by 9 is: 1000/9000 1000 / 9000 =1/9 = 1 / 9 The required answer is 1/9 1 / 9 .
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