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Anna007 [38]
2 years ago
13

We choose a 4-digit number randomly. What is the probability that all its digits are even? help asap

Mathematics
2 answers:
Vlad1618 [11]2 years ago
5 0

Answer:

It's very simple. In 4 decimal digits there are 10,000 (0000 to 9999) possible values. The odds of any one of them coming up randomly is one in 10,000. A specific "4 digit number" would have 1/9000 chance, since there are 9000 4 digit numbers (1000-9999).

Step-by-step explanation:

dolphi86 [110]2 years ago
3 0
There are 9,000 true 4 digit numbers and out of that 1000 numbers are divisible by 9.

The probability is given by Favourable Possibilities divided by Total Possibilities.

In the current case, the probability that the number is divisible by 9 is:

1000/9000
1000
/
9000

=1/9
=
1
/
9

The required answer is 1/9
1
/
9
.
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4(9-x)6-6(4-7x)>5(1-2x)-8x+9(6-x)
Kazeer [188]

Answer:

x > 133/45

WORKING :

Multiply the number : 4 . 6 = 24

24(9-x) - 6 (4 - 7x) > 5 (1 - 2x) - 8x + 9 (6-x)

expand 24(9 - x) - 6(4 -7x) : 18x + 192

expand 5(1-2x) - 8x + 9(6-x) : - 27x + 59

18x + 192 > -27x + 59

subtract 192 from both sides

18x + 192 - 192 > -27x + 59 - 192

simplify

18x > -27x - 133

add 27x to both sides

18x + 27x > - 27x - 133 + 27x

simplify

45x > - 133

Divide both sides by 45

45x/45 > 133/45

Simplify

x > 133/45

FINALLY ANSWER :

X > 133/45

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