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kow [346]
3 years ago
7

In April, a Jamaican tourist changed JM $50,000 into American currency. Calculate the amount of US dollars he received. USD $1.0

0 = JMD $146
Mathematics
1 answer:
suter [353]3 years ago
7 0

Answer:

USD $342.47

Step-by-step explanation:

For these kinds of questions, I like to use what I call the 'I want... If' method. I'll walk you through my thought process. Essentially, when I write my formula, I think, 'I want to find out how many US dollars I can receive from JMD $50,000 if JMD $146 is USD $1.

Essentially, the 'I want to find out... $50,000' part goes in the nominator of a fraction. 'If JMD $146' goes in the denominator of the same fraction. Then, add a multiply operator and finally 'is USD $1' goes after the operator.

In working, it looks like this:

JMD $\frac{50000}{146} x USD $1 = USD $342.4657534247 = USD $342.47 (To 3 s.f.)

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garik1379 [7]

Answer:

\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}

Step-by-step explanation:

We want to find the equation of the line tangent to the graph of:

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So, we will find the derivative of our equation first. Applying the chain rule, we acquire that:

\displaystyle y^\prime=\frac{1}{\sqrt{1-(\frac{x}{5})^2}}\cdot\frac{1}{5}

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\displaystyle y^\prime=\frac{1}{5\sqrt{1-\frac{x^2}{25}}}

We can factor out the denominator within the square root:

\displaystyle y^\prime =\frac{1}{5\sqrt{\frac{1}{25}\big(25-x^2)}}

Simplify:

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So, we can find the slope of the tangent line at <em>x</em> = 5/2. By substitution:

\displaystyle y^\prime=\frac{1}{\sqrt{25-(5/2)^2}}

Evaluate:

\displaystyle y^\prime=\frac{1}{\sqrt{75/4}}=\frac{1}{\frac{5\sqrt{3}}{2}}=\frac{2\sqrt{3}}{15}

We will also need the point at <em>x</em> = 5/2. Using our original equation, we acquire that:

\displaystyle y=\sin^{-1}(\frac{1}{2})=\frac{\pi}{6}

So, a point is (5/2, π/6).

Finally, by using the point-slope form, we can write:

\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}(x-\frac{5}{2})

Distribute:

\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}x+\frac{-\sqrt{3}}{3}

Isolate. Hence, our equation is:

\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}

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<h3>What is simple interest and compound interest?</h3>

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