Hi there!
To split 90 kilos in the ratio of 2 : 3 : 7 we must first realise that we have a total of 2 + 3 + 7 = 12 parts, in which we must split the total 90 kilos.
12 parts equal 90 kilo, and therefore
1 part equals 90 / 12 = 7.5 kilos.
1 part equals 90 / 12 = 7.5 kilos, and therefore
2 parts equal 7.5 × 2 = 15 kilos.
1 part equals 90 / 12 = 7.5 kilos, and therefore
3 parts equal 7.5 × 3 = 22.5 kilos.
1 part equals 90 / 12 = 7.5 kilos, and therefore
7 parts equal 7.5 × 7 = 52.5 kilos.
Hence, 90 kilos in the ratio of 2 : 3 : 7
gives 15 kg, 22.5 kg and 52.5 kg.
~ Hope this helps you!
Answer:
2.99m-4 (less than or equal to symbol after) 20
Step-by-step explanation:
This would come out too 5 movies because 20-4= 16 16-2.99=5.3 but it is impossible to buy 5.3 movies so you would round it down to 5
It means the variable y is equal to the negative variable of x.
Answer:
C) Uniform distribution
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely. In this case, the probability of producing a defective light bulb from a production line is the same over an interval of 90 minutes, so the correct answer is C.
We can calculate the probability.
Uniform probability distribution
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X lower than x is given by the following formula.
For this problem, we have that:
Uniformily distributed over a 90 minute interval, that is, between 0 and 90, so 
and 
.
We want to find 
Answer: Probability P = 1/1716
Step-by-step explanation:
Definition
For permutation ( order is important)
nPr = n!/(n-r)!
Given;
Total number of members in the committee = 13
Total number of members to be selected = 3
Since order is important in this case.
The total number (Tt) of possible ways of selecting three executives from the committee members is given as
Tt = 13P3 (since order is important)
Tt = 13!/(13-3)!
Tt = 13!/10!
Tt = 1716
The probability P of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions is equal to
P = number of favourable outcomes/ number of possible outcomes
Number of favourable outcomes = 1 (i.e 1×1×1 = 1) one option for each post.
Number of possible outcomes = Tt = 1716
P = 1/1716
