C
You split inequality into
2x-2>8 and 2x—2<-8
X>5. X<-3
Answer:
No
Step-by-step explanation:
Let's find the slope of both lines and then compare these slopes:
From (-4,3) to (-5,4) entails a decrease of -1 in x and an increase of 1 in y. Thus, the slope is m = rise / run = 1/(-1) = -1.
From (0,1) to (5,0) entails an increase of 5 in x and a decrease of 1 in y. The slope here is m = rise / run = -1/5.
For these lines to be parallel, their slopes must be the same. That is not the case here, so NO, the lines are not parallel.
The answer to your question is = 148.06
Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33
