10512 is the answer since you just move the decimal place over to the right three times.
Answer:
he score is 2.15 standard deviations above the mean.
Step-by-step explanation:
B. First off , standard form of a 2nd degree equation is Ax^2 + Bx + C. So look at the coefficient of Ax^2 which is -2.
If positive, the parabola opens up and has a minimum.
If negative, the parabola opens down and has a maximum.
A. To find the vertex (in this case maximum),
Graph the equation -OR—
make a table. — OR—
Find the zeroes and find the middle x-value
-2x^2 - 4x + 6
-2(x^2 +2x - 3 = 0
-2 (x - 1) ( x + 3)=0
x - 1 = 0. x + 3 = 0
x = 1. x = -3. So halfway would be at (-1, __).
Sub in -1 into original equation -2x^2 -4x + 6 … -2(-1)^2 -4(-1) + 6 = -2 +4 +6 = 8
So the vertex is (-1,8)
2/9 + 4/9
first add them and then divide to get the simplest form ....
=6/9
=2/3 ...
Hope it helps !!!
A trapezium is a quadrilateral. The option that is true for the trapezium is A, D, and E.
<h3>What is Trapezium?</h3>
A trapezium is a quadrilateral which is having a pair of opposite sides as parallel and the length of the parallel sides is not equal.
The given trapezium is an isoceles trapezium. Therefore, the properties of the trapezium that are true for KLMJ are:
- KL is parallel to JM
- ∠J is supplementary ∠K
- ∠J is congruent to ∠M (Valid only for isoceles trapezium).
Hence, the option that is true for the trapezium is A, D, and E.
Learn more about Trapezium:
brainly.com/question/22607187
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