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BARSIC [14]
3 years ago
8

What is the least common multiple of 35 and 17? PLEASE HELP ME!!!​

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

595

Step-by-step explanation:

ez

Andreas93 [3]3 years ago
5 0

Answer:

595

Step-by-step explanation:

can i have brainliest

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EASY Work!! Please look at the picture and yes it’s easy for other people but not me for people asking.
Keith_Richards [23]

Answer:

7()=11

8()=42

I could barely see the answer for number 9 sorry :(

Step-by-step explanation:

the 7() is 2(3)+5

2(3)=6

6+5=11

Question (8)

c^2+3a x b

c(6)^2+ 3(3) x 2/3

36+9 x 2/3

36+6=42

7 0
3 years ago
Read 2 more answers
Juan bought a gift for his friend. He wants to place the gift in a package with the length of 8 inches, width of 7 inches, and t
creativ13 [48]
266 is the answer 

hope u saw this in time 
3 0
3 years ago
a relay team of 4 people runs 3 mile. it each person runs the same distance, how many miles does each person run?
Bingel [31]
Each person runs 3/4 miles.
6 0
3 years ago
the ratio of students with bikes to students with scooters in the school is 85:51. What is the greatest common factor that you c
Vikentia [17]
Answer:GCF=17

To find the greatest common factor, or GCF, of the numbers, we first need to list the prime factors of both 85 and 51

52=3*17

85=5*17

17 is the sole common factor that these two numbers have in common, therefore 17 is the GCF.

To simplify the ratio, simply divide both numbers by 17.

85:51 becomes 5:3
5 0
3 years ago
Read 2 more answers
An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
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