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irakobra [83]
3 years ago
10

18 2by5-4 1by10 find the difference

Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Given:

The expression is:

18\dfrac{2}{5}-4\dfrac{1}{10}

To find:

The difference.

Solution:

We have,

18\dfrac{2}{5}-4\dfrac{1}{10}

It can be rewritten as:

=\dfrac{90+2}{5}-\dfrac{40+1}{10}

=\dfrac{92}{5}-\dfrac{41}{10}

Taking LCM, we get

=\dfrac{184-41}{10}

=\dfrac{143}{10}

=\dfrac{140+3}{10}

=14\dfrac{3}{10}

Therefore, the value of the difference is 14\dfrac{3}{10}.

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Step-by-step explanation:

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Vedmedyk [2.9K]

Answer:

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Step-by-step explanation:

For confidence interval of 99%, the range is (0.005, 0.995). Using a z-table, the z-score for 0.995 is 2.58.

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Proportion is unknown. So, worse case proportion is 50%. p = 50% = 0.5.

\\ n = \left(\frac{\texttt{z-score}}{\texttt{margin of error}} \right )^2\cdot p\cdot (1-p) \\ = \left(\frac{2.58}{0.002} \right )^2\cdot 0.5\cdot (1-0.5)=416025

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3 years ago
Can anyone Help I have 25 questions, 2hr 40mins remaining,
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Combining the like-terms, the result of the addition of polynomials f(x) and g(x) is given by:

f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}

<h3>How do we add polynomials?</h3>

We add polynomials combining the like-terms, that is, adding terms with the same exponent.

In this problem, the polynomials are:

  • f(x) = 3x^{\frac{1}{2}} + 7x^{-\frac{1}{4}} + 8x^{-4}
  • g(x) = -\frac{7}{4}x^{\frac{1}{2}} + 12x^{-\frac{1}{4}} - 21x^3

Combining the like terms, the addition is given by:

f(x) + g(x) = \left(3 - \frac{7}{4}\right)x^{\frac{1}{2}} + (7 + 12)x^{-\frac{1}{4}} + 8x^{-4} + 21x^3

f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}

More can be learned about addition of polynomials at brainly.com/question/9438778

#SPJ1

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2 years ago
If tan a = 9/40<br>use trigonometric identities to find the values of sin a and cos a.​
Sindrei [870]

Answer:

see explanation

Step-by-step explanation:

Given

tan a = \frac{9}{40} = \frac{opposite}{adjacent}

We require the hypotenuse h

Using Pythagoras' identity

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h = \sqrt{1681} = 41 , thus

sin a = \frac{opposite}{hypotenuse} = \frac{9}{41}

cos a = \frac{adjacent}{hypotenuse} = \frac{40}{41}

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3 years ago
Are the expressions 5 ( x - 3) and 5x + 15 equivalent? use the distributive property to support your answer
ratelena [41]

Answer: No

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I hope this helps!

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