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3 years ago

Determine the slope PLS HELP AND HURRRRRRYYYYYYYYYYYYY

Mathematics

1 answer:

levacccp [35]3 years ago

7 0

Answer:

You see where ANY two intersection of the line touch the grid. Then you do the rise/run (y/x) method.

The answer is 3/4.

Because it rises 3 times and runs 4 times.

BRAINLIEST!!

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Jenny has been saving quarters in a piggy bank since she was born. She currently has 192 quarters in her piggy bank. She wants t

Mashutka [201]

The answer is D because....
192/4
$48
From that you can eliminate A and C.
Solve for B and D knowing that she needs 27 more dollars.
216/4= 54 *No*
108/4= 27 *Yes*
$48+$27= $75

8 0

3 years ago

Please help with answer and number line

goblinko [34]

Answer:

Graph uploaded!

Step-by-step explanation:

<u>First, let's solve the distributive property.</u>

4/5(x - 2) ≤ 6
=> 4x/5 - 8/5 ≤ 6
=> 4x/5 ≤ 6 + 8/5
=> 4x/5 ≤ 38/5
=> x ≤ 19/2

Now, let's plot this inequality on the line. Please check my graph.

Hoped this helped!

6 0

2 years ago

A student is given data that follows a normal distribution. According to the data, the mean amount of time that students spent r

sergejj [24]

Answer:

a. Only 68% of the students will fall in the range of 10- 2 and 10 + 2 hours.

Step-by-step explanation:

He appies the empirical 68-95-99.7 rule, where 68% of the data is expected to be within ne standard deviation from the mean, to the right and to the left.

Half of this (68%/2=34%) will be between the mean and one deviation standard to the right. This is between 10 hours and 10+2=12 hours.

The right answer is:

a. Only 68% of the students will fall in the range of 10- 2 and 10 + 2 hours.

6 0

3 years ago

Write an equivalent expression for the 4th root of 324m^12 * the cubed root of 64k^9. Need help!

Elis [28]

Answer:

The equivalent expression to the givan expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

To find the equivalent expression to the given expression :

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

$=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})$

$=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})$

$=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)$

$=3\sqrt[4]{4}m^3.4k^3$

$=12\sqrt[4]{4}m^3k^3$

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Therefore the equivalent expression to the given expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

8 0

3 years ago

An occluded front moves over farmland that has been experiencing drought conditions, what change in weather will this front like

lora16 [44]

When an ocluded front moves over farmland that has been in a drought then an extended period of rain happens. This beasically happens because <span>the cold air mass from the cold front meets the cool air that was ahead of the warm front. The warm air rises as these air masses come together.</span>

6 0

4 years ago

Read 2 more answers